Answer:
simple
Explanation:
use nordvpn with discount code: Chonchode
Answer:
#include <stdio.h>
typedef struct TimeHrMin_struct //struct
{
int hours;
int minutes;
} TimeHrMin;
struct TimeHrMin_struct SetTime(int hoursVal,int minutesVal) //SetTime function
{
struct TimeHrMin_struct str;
str.hours=hoursVal; //assigning the values
str.minutes=minutesVal;
return str; //returning the struct
}
int main(void)
{
TimeHrMin studentLateness;
int hours;
int minutes;
scanf("%d %d", &hours, &minutes);
studentLateness = SetTime(hours, minutes); //calling the function
printf("The student is %d hours and %d minutes late.\n", studentLateness.hours, studentLateness.minutes);
return 0;
}
Explanation:
Answer:
public class Digits
{
public static boolean allDigitsOdd(int num)
{
boolean flag=true;
int rem;
while(num>0)
{
rem=num%10;
num=num/10;
if(rem%2==0) // if a even digit found immediately breaks out of loop
{
flag=false;
break;
}
}
return flag; //returns result
}
public static void main(String args[])
{
System.out.println(allDigitsOdd(1375)); //returns true as all are odd digits
}
}
OUTPUT :
true
Explanation:
Above program has 2 static methods inside a class Digits. Logic behind above function is that a number is divided by 10 until it is less than 0. Each time its remainder by 0 is checked if even immediately breaks out of the loop.
(Disclaimer: I am not a professional, so it might not be the most concise answer possible, but I did run the Python script and it works)
Answer:
user_input = input("What food do you have in your refrigerator? ").lower()
count = 0
while True:
if user_input != 'apples':
count += 1
print(f'You have a {user_input} with a total of {count} food(s)\n')
user_input = input("What food do you have in your refrigerator? ")
else:
break
It looks like you need to get both numbers from the input. Try doing something like this:
print(int(input()) + int(input()))
