2/9 is in simplest form as 2 and 9 do not have any common factors.
Answer:
18 years, 4 months and 10 days.
Step-by-step explanation:
Given that the person invests $ 1000 in an account with compound interest each month, with an interest rate of 6%, to determine how long the investment must maintain to reach $ 3,000, the following calculation must be performed:
3,000 = 1,000 (1 + 0.06 / 12) ^ Yx12
3,000 = 1,000 (1 + 0.06 / 12) ^ 18.36x12
3,000 = 3,000
Therefore, the person must keep his investment for a period of 18.36 years. Since 12 x 0.36 is equal to 4.32, the total investment time should be 18 years, 4 months and 10 days.
Answer:
m∠CAD = 49degrees
Step-by-step explanation:
For a rectangle ABCD if m∠BAC=4x+5and m∠ACD=5x−4, then;
m∠BAC = m∠ACD (alternate angles)
4x+5 = 5x - 4
4x-5x = -4-5
-x = -9
x = 9
Also
m∠BAC+m∠CAD = 90
4x+5+m∠CAD = 90
4(9)+5+m∠CAD = 90
36+5+m∠CAD = 90
41+m∠CAD = 90
m∠CAD = 90-41
m∠CAD = 49degrees
First, let's find the x and y intercepts
In the first equation
y - 4x = -1
Put x =0
y= - 1
(0, -1)
Put y=0 and the n solve for x
0 - 4x = -1
-4x = -1
x=0.25
(0.25 , 0)
The points for the first equation is (0, -1 ) and (0.25, 0)
Next is to find the intercts for the second equation
y + x = 4
put x=0
y = 4
(0, 4)
Put y =0
0 + x = 4
x = 4
( 4, 0)
The points for the second equation are;
(0, 4) and (4, 0)
Below is the graph
Answer:
maybe 3/5
Step-by-step explanation:
I hope it's right