Answer:
Multiplication and Division unless there are parentheses
Step-by-step explanation:
Answer:

Step-by-step explanation:
Considering the expression

Lets determine the expansion of the expression




Expanding summation








as





so equation becomes


Therefore,
15. 3x - 2y = -2
3x - 3x - 2y = -3x - 2
-2y = -3x - 2
-2 -2
y = 1.5x + 1
y - y₁ = m(x - x₁)
y - 3 = ⁻²/₃(x - (-2))
y - 3 = ⁻²/₃(x + 2)
y - 3 = ²/₃(x) - ²/₃(2)
y - 3 = ⁻²/₃x - 1¹/₃
+ 3 + 3
y = ⁻²/₃x + 1²/₃
16. 230 = 0.2s + 150
- 150 - 150
80 = 0.2s
0.2 0.2
400 = s
17. y = 2x + 2
Answer:
- 7/4
Step-by-step explanation:
y1 - y2 over x1 - x2 with the points (-3,4) and (1,-3)
-3 - 4 over 1 - (-3) --> -7/ 4
195 is the answer because you replace x with 10
Step-by-step explanation:
825-630=195