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4 years ago

Measure of angle LOI= 38 degrees Measure of angle JOP= 84 degrees Find measure of angle JKP

Mathematics

1 answer:

Bogdan [553]4 years ago

3 0

Answer:

The measure of angle JKP is 61°

Step-by-step explanation:

we know that

If the measure of angle m<LOI=38°

then

m arc IL=38° -----> by central angle

and

If the measure of angle m<JOP=84°

then

m arc JP=84° -----> by central angle

Remember that

The measure of the interior angle is the semi-sum of the arcs that comprise it and its opposite.

m<JKP=(1/2)[arc IL+arc JP]

substitute the values

m<JKP=(1/2)[38°+84°]=61°

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3 years ago

7a +42 +8< -10 + 9a -64a

Mamont248 [21]

Answer:

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General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
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Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

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Terms/Coefficients

Step-by-step explanation:

Step 1: Define

7a + 42 + 8 < -10 + 9a - 64a

Step 2: Solve for a

Combine like terms (a): 7a + 42 + 8 < -10 - 55a
Combine like terms: 7a + 50 < -10 - 55a
[Addition Property of Equality] Add 55a on both sides: 62a + 50 < -10
[Subtraction Property of Equality] Subtract 50 on both sides: 62a < -60
[Division Property of Equality] Divide 62 on both sides: a < -30/31

Here we see any number a less than -30/31 would work as a solution to the inequality.

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3 years ago

If tan 2A = cot (A -18°), where 2A is an acute angle, find the value of A.

Reptile [31]

answer will be -24

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3 years ago

Read 2 more answers

I don't understand this question at all please help if you do

lorasvet [3.4K]

Answer:

Answer is $\frac{4}{3}$

Step-by-step explanation:

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Using Desmos I have Graphs of both of the equations you have provided. The problem asks us to find the shaded region between those curves/equations.

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