Answer:
√10
------
5
Step-by-step explanation:
√(2/5) has a radical in the denominator. We want to eliminate that radical. To do this, multiply both √2 and √5 by √5:
√2·√5
----------
5
This simplifies to
√10
------
5
Answer:
Step-by-step explanation:
The formula for point slope is: 
When:
m = slope
(x1,y1) = the point on the graph
-9 is the slope, so it replaces m. x1 is -1, and y1 is -3.
Plug in the values:
OR
Answer:
3 x^2 - x + -1
Step-by-step explanation:
Simplify the following:
-(4 x - 2 x^2 - 3) + x^2 + 3 x - 4
Factor -1 out of -2 x^2 + 4 x - 3:
--(2 x^2 - 4 x + 3) + x^2 + 3 x - 4
(-1)^2 = 1:
2 x^2 - 4 x + 3 + x^2 + 3 x - 4
Grouping like terms, 2 x^2 + x^2 + 3 x - 4 x - 4 + 3 = (x^2 + 2 x^2) + (3 x - 4 x) + (-4 + 3):
(x^2 + 2 x^2) + (3 x - 4 x) + (-4 + 3)
x^2 + 2 x^2 = 3 x^2:
3 x^2 + (3 x - 4 x) + (-4 + 3)
3 x - 4 x = -x:
3 x^2 + -x + (-4 + 3)
3 - 4 = -1:
Answer: 3 x^2 - x + -1
I am assuming that the cost of an oil change already includes the mark-up.
So, 18 is 175%. 18 ÷ 1.75 = 10.29 is the original cost.
10.29 * 3/4 = 30.87/4 = 7.71 mark-up
10.29 + 7.71 = 18
Or if 18 is the basis of the mark-up, then,
18 * 3/4 = 54/4 = 13.50 mark-up
18 + 13.50 = 31.50 new cost of an oil change
Answer:
Answered and explained below
Step-by-step explanation:
A) We are told that frequency of the trait is still 1 in 8. Thus, population proportion; p = 1/8 = 0.125
Sample size; n = 150
Formula for mean is;
μ = np
μ = 150 × 0.125
μ = 18.75
Formula for standard deviation is;
σ = √(np(1 - p))
σ = √(150 × 0.125(1 - 0.125))
σ = √16.40625
σ = 4.05
B) usually, when np ≥ 10 , we make use of normal distribution.
I'm this case, it is 18.75 which is greater than 10.
Thus,we can use a normal model to approximate the distribution.
C) we are told that he found the trait in 22 of the frogs.
Thus;
Proportion is now; 22/150 = 0.1467
This is a higher probability that the initial one of 0.125 and we can say that the trait has become more common.
