Question

Based on concerns raised by his preliminary research, the biologist decides to collect and examine 150 frogs.

Answer 1

Answer:

Answered and explained below

Step-by-step explanation:

A) We are told that frequency of the trait is still 1 in 8. Thus, population proportion; p = 1/8 = 0.125

Sample size; n = 150

Formula for mean is;

μ = np

μ = 150 × 0.125

μ = 18.75

Formula for standard deviation is;

σ = √(np(1 - p))

σ = √(150 × 0.125(1 - 0.125))

σ = √16.40625

σ = 4.05

B) usually, when np ≥ 10 , we make use of normal distribution.

I'm this case, it is 18.75 which is greater than 10.

Thus,we can use a normal model to approximate the distribution.

C) we are told that he found the trait in 22 of the frogs.

Thus;

Proportion is now; 22/150 = 0.1467

This is a higher probability that the initial one of 0.125 and we can say that the trait has become more common.