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3 years ago

How do i automate survey monkey results to my email

Computers and Technology

1 answer:

NARA [144]3 years ago

3 0

Answer:

(Hope this helps can I pls have brainlist (crown) ☺️)

Explanation:

To send an Email Invitation, go to the Collect Responses section and choose Send via Email. Click Next when you've finished writing your invitation message. Select Confirmation Email from the drop-down menu. Select On, and each responder will receive a confirmation email with a copy of their replies.

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Write a program with the total change amount as an integer input, and output the change using the fewest coins, one coin type pe

riadik2000 [5.3K]

Answer:

In Python:

cents = int(input("Cents: "))

dollars = int(cents/100)

quarters = int((cents - 100*dollars)/25)

dimes = int((cents - 100*dollars- 25*quarters)/10)

nickels = int((cents - 100*dollars- 25*quarters-10*dimes)/5)

pennies = cents - 100*dollars- 25*quarters-10*dimes-5*nickels

if not(dollars == 0):

if dollars > 1:

print(str(dollars)+" dollars")

else:

print(str(dollars)+" dollar")

if not(quarters == 0):

if quarters > 1:

print(str(quarters)+" quarters")

else:

print(str(quarters)+" quarter")

if not(dimes == 0):

if dimes > 1:

print(str(dimes)+" dimes")

else:

print(str(dimes)+" dime")

if not(nickels == 0):

if nickels > 1:

print(str(nickels)+" nickels")

else:

print(str(nickels)+" nickel")

if not(pennies == 0):

if pennies > 1:

print(str(pennies)+" pennies")

else:

print(str(pennies)+" penny")

Explanation:

A prompt to input amount in cents

cents = int(input("Cents: "))

Convert cents to dollars

dollars = int(cents/100)

Convert the remaining cents to quarters

quarters = int((cents - 100*dollars)/25)

Convert the remaining cents to dimes

dimes = int((cents - 100*dollars- 25*quarters)/10)

Convert the remaining cents to nickels

nickels = int((cents - 100*dollars- 25*quarters-10*dimes)/5)

Convert the remaining cents to pennies

pennies = cents - 100*dollars- 25*quarters-10*dimes-5*nickels

This checks if dollars is not 0

if not(dollars == 0):

If greater than 1, it prints dollars (plural)

if dollars > 1:

print(str(dollars)+" dollars")

Otherwise, prints dollar (singular)

else:

print(str(dollars)+" dollar")

This checks if quarters is not 0

if not(quarters == 0):

If greater than 1, it prints quarters (plural)

if quarters > 1:

print(str(quarters)+" quarters")

Otherwise, prints quarter (singular)

else:

print(str(quarters)+" quarter")

This checks if dimes is not 0

if not(dimes == 0):

If greater than 1, it prints dimes (plural)

if dimes > 1:

print(str(dimes)+" dimes")

Otherwise, prints dime (singular)

else:

print(str(dimes)+" dime")

This checks if nickels is not 0

if not(nickels == 0):

If greater than 1, it prints nickels (plural)

if nickels > 1:

print(str(nickels)+" nickels")

Otherwise, prints nickel (singular)

else:

print(str(nickels)+" nickel")

This checks if pennies is not 0

if not(pennies == 0):

If greater than 1, it prints pennies (plural)

if pennies > 1:

print(str(pennies)+" pennies")

Otherwise, prints penny (singular)

else:

print(str(pennies)+" penny")

4 0

3 years ago

Write a program that asks the user to enter a number within the range of 1 through 10. Use a switch statement to display the Rom

Studentka2010 [4]

Answer:

// program in C++.

// headers

#include <bits/stdc++.h>

using namespace std;

// main function

int main()

{

// Variable

int num;

cout << "Enter a number between 1 and 10: ";

// read input

cin >> num;

// validate input number

while(num<1||num>10)

{

// if input is wrong then print error message

cout<<"Wrong input!!Enter again:";

// read again

cin>>num;

}

// print output

cout << "The Roman numeral for "<<num<<" is:";

// switch

switch (num)

{

case 1:

// if input is 1

cout<<"I"<<endl;

// exit the switch

break;

case 2:

// if input is 2

cout<<"II"<<endl;

// exit the switch

break;

case 3:

// if input is 3

cout<<"III"<<endl;

// exit the switch

break;

case 4:

// if input is 4

cout<<"IV"<<endl;

// exit the switch

break;

case 5:

// if input is 5

cout<<"V"<<endl;

// exit the switch

break;

case 6:

// if input is 6

cout<<"VI"<<endl;

// exit the switch

break;

case 7:

// if input is 7

cout<<"VII"<<endl;

// exit the switch

break;

case 8:

// if input is 8

cout<<"VIII"<<endl;

// exit the switch

break;

case 9:

// if input is 9

cout<<"IX"<<endl;

// exit the switch

break;

case 10:

// if input is 10

cout<<"X"<<endl;

// exit the switch

break;

// default

default:

break;

}

return 0;

}

Explanation:

Read a number from usr and assign it to variable "num". If the input number is less than 1 or greater than 10 then ask again to enter a number until user enter a number between 1-10 only.Then with the help of switch() function print the equivalent Roman number.

Output:

Enter a number between 1 and 10: -5

Wrong input!!Enter again:12

Wrong input!!Enter again:6

The Roman numeral for 6 is:VI

7 0

3 years ago

Every type of internet service requires a connection and monthly payment to a(n): isp voip lms mmorpg

Rainbow [258]

Every type of Internet service requires a connection and monthly payment to an internet server provider. An Internet service provider or as called as ISP is a company that offers customers with internet access. The data may be conveyed using several technologies as well as dial-up, DSL, cable modem, wireless or enthusiastic high-speed interrelates.

6 0

4 years ago

Which describes a design theme in PowerPoint? a set of elements that unify the slides and complement the topic a printed handout

chubhunter [2.5K]

a set of elements that unify the slides and complement the topic

5 0

4 years ago

Read 2 more answers

Write a program to determine the addresses of memory locations allocated to various variables as follow:

Andreas93 [3]

Here you go,

PROGRAM

#include<stdio.h>

#include<stdlib.h>

int main()

{

short int a,b;

int c,d;

long int e,f;

short int size_short,size_int,size_long_int;

//printing address of variable using void pointer

printf("\nAddress of first short int variable : %p", (void*)&a);

printf("\nAddress of second short int variable : %p", (void*)&b);

printf("\n\nAddress of first int variable : %p", (void*)&c);

printf("\nAddress of second int variable : %p", (void*)&d);

printf("\n\nAddress of first long int variable : %p", (void*)&e);

printf("\nAddress of second long int variable : %p", (void*)&f);

//calculating size by subtracting memory address

size_short = (short int)((void*)&a - (void*)&b);

size_int = (short int)((void*)&c - (void*)&d);

size_long_int = (short int)((void*)&e - (void*)&f);

printf("\n\nsize of short variable by subtracting address : %u", size_short);

printf("\n size of short variable by using sizeof() : %u", sizeof(a));

printf("\n\nsize of int variable by subtracting address : %u", size_int);

printf("\n size of int variable by using sizeof() : %u", sizeof(c));

printf("\n\nsize of long int variable by subtracting address : %u", size_long_int);

printf("\n size of long variable by using sizeof() : %u", sizeof(e));

return 0;

}

5 0

4 years ago