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Goryan [66]
3 years ago
13

A restaurant produces 250 meals per day with five employees. After hiring an additional employee, the restaurant now produces 26

0 meals per day. Calculate the marginal product of labor
A.260
B. 10
C. 5/3
D. 2
Mathematics
2 answers:
Stolb23 [73]3 years ago
7 0

Answer:

The answer is D

Step-by-step explanation:

Hope this helps UwU

elena-14-01-66 [18.8K]3 years ago
3 0
The answer is D. They added an employee.
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HELP ASAP!!
Alona [7]

Answer:

The answer is C) - |x - 2| + 3 = 0

Step-by-step explanation:

a) - |x - 2| + 3 > 0

The greater than means something above the graph.

b) - |x - 2| + 3 < 0

The less than means something below the graph.

c) - |x - 2| + 3 = 0

The zero doesn't do anything.

y = - a |x - h| + k = 0

(h,k) is the origin.

h is shift left/right, h = 2 so shift right 2.

k is shift up/down, k = 3 so shift up 3.

The a, affects the y-values which cause the graph to reflect across the x-axis.

6 0
2 years ago
Describe how you could represent the fraction 4/10 using a model or number line
zubka84 [21]

Answer:

Not going to give answer, but let you solve

Step-by-step explanation:

You first have to start by drawing a number line and mark two integers between the fraction lines. Then you have to divide the section between the two integers in an equal number of parts which is equal to the denominator.

Hope I helped

5 0
2 years ago
In ΔVWX, v = 390 inches, w = 390 inches and x=500 inches. What is the sum of ∠Vand∠W?
Stolb23 [73]
The answer would be 390+ 390 =780
6 0
3 years ago
1.Find the compound interest on Rs25000 for 3 years at 10% per annum ,Compounded annually.
LekaFEV [45]

Answer:

The compound interest is Rs8275

Step-by-step explanation:

The rule of the compound interest is A = P(1+\frac{r}{n})^{nr}, where

  • A is the new amount
  • P is the initial amount
  • r is the interest rate in decimal
  • n is the number of periods
  • t is the time

The interest I = A - P

∵ The amount of investment is Rs25000 for 3 years

∴ P = 25000

∴ t = 3

∵ The rate of interest is 10% per annum, compounded annually

∴ r = 10% = 10 ÷ 100 = 0.1

∴ n = 1 ⇒ compounded annually

→ Substitute these value in the 1st rule above to find the new amount

∵ A = 25000(1+\frac{0.1}{1})^{1(3)}

∴ A = 25000(1.1)^{3}

∴ A = Rs33275

→ Use the 2nd rule above to find the interest

∵ I = 33275 - 25000

∴ I = 8275

∴ The compound interest is Rs8275

6 0
2 years ago
A Cepheid variable star is a star whose brightness alternately increases and decreases. For a certain star, the interval between
sattari [20]

Answer:

a)

B'(t) = \dfrac{0.9\pi}{4.4}\cos\bigg(\dfrac{2\pi t}{4.4}\bigg)

b) 0.09

Step-by-step explanation:

We are given the following in the question:

B(t) = 4.2 +0.45\sin\bigg(\dfrac{2\pi t}{4.4}\bigg)

where B(t) gives the brightness of the star at time t, where t is measured in days.

a) rate of change of the brightness after t days.

B(t) = 4.2 +0.45\sin\bigg(\dfrac{2\pi t}{4.4}\bigg)\\\\B'(t) = 0.45\cos\bigg(\dfrac{2\pi t}{4.4}\bigg)\times \dfrac{2\pi}{4.4}\\\\B'(t) = \dfrac{0.9\pi}{4.4}\cos\bigg(\dfrac{2\pi t}{4.4}\bigg)

b) rate of increase after one day.

We put t = 1

B'(t) = \dfrac{0.9\pi}{4.4}\cos\bigg(\dfrac{2\pi t}{4.4}\bigg)\\\\B'(1) = \dfrac{0.9\pi}{4.4}\bigg(\cos(\dfrac{2\pi (1)}{4.4}\bigg)\\\\B'(t) = 0.09145\\B'(t) \approx 0.09

The rate of increase after 1 day is 0.09

8 0
3 years ago
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