Answer:
it like the Same question I asked and I told u to draw a graph then solve
The greatest whole possible whole number length of the unknown side is 9 inches.
<h3>How to identify if a triangle is acute?</h3>
Let us have:
H = biggest side of the triangle
And let we get A and B as rest of the two sides.
Then we get:
If
then the triangle is acute
Two sides of an acute triangle measure as 5 inches and 8 inches
The length of the longest side is unknown.
We have to find the length of the unknown side
WE know that the longest side of any triangle is a hypotenuse
For an acute triangle we know:
Here in this sum,
a = 5 inches
b = 8 inches
c = ?
Substituting we get,
c < 9
Hence, The greatest whole possible whole number length of the unknown side is 9 inches.
Learn more about angles;
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Solve the equation of the function for n.
a(n) = 3n - 20
a = 3n - 20
a + 20 = 3n
(a + 20)/3 = n
n = (a + 20)/3
n(a) = (a + 20)/3
Answer:
y = 2cos5x-9/5sin5x
Step-by-step explanation:
Given the solution to the differential equation y'' + 25y = 0 to be
y = c1 cos(5x) + c2 sin(5x). In order to find the solution to the differential equation given the boundary conditions y(0) = 1, y'(π) = 9, we need to first get the constant c1 and c2 and substitute the values back into the original solution.
According to the boundary condition y(0) = 2, it means when x = 0, y = 2
On substituting;
2 = c1cos(5(0)) + c2sin(5(0))
2 = c1cos0+c2sin0
2 = c1 + 0
c1 = 2
Substituting the other boundary condition y'(π) = 9, to do that we need to first get the first differential of y(x) i.e y'(x). Given
y(x) = c1cos5x + c2sin5x
y'(x) = -5c1sin5x + 5c2cos5x
If y'(π) = 9, this means when x = π, y'(x) = 9
On substituting;
9 = -5c1sin5π + 5c2cos5π
9 = -5c1(0) + 5c2(-1)
9 = 0-5c2
-5c2 = 9
c2 = -9/5
Substituting c1 = 2 and c2 = -9/5 into the solution to the general differential equation
y = c1 cos(5x) + c2 sin(5x) will give
y = 2cos5x-9/5sin5x
The final expression gives the required solution to the differential equation.
Step-by-step explanation:
I am not sure this is a square.
this could be a rectangle.
to be safe, I am following that path.
in a rectangle opposite sides are of equal length.
that means
y - 1 = 2y - 7
y = 2y - 6
0 = y - 6
y = 6
3x - 4 = 3y - 13
3x - 4 = 3×6 - 13
3x - 4 = 18 - 13 = 5
3x = 9
x = 3
as it turns out, it is a square, so we could have used every side expression to be equal with every other side expression, but better safe than sorry ...
