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sweet [91]
2 years ago
6

Write an algorithm to solve the problem with long division. Answer in at least 3 complete sentences.​

Mathematics
1 answer:
Tamiku [17]2 years ago
7 0

Answer:

1) Divide; 2) Multiply; 3) Subtract; 4) Drop down the next digit. Of these steps, #2 and #3 can become difficult and confusing to students

Step-by-step explanation:

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I think its the second one, im not quite sure.

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22x – 54 + 5.736x^4 - 2x^2<br> Standard form
Yuri [45]

Answer:

5.736x^4 - 2x^2 +22x - 54

Step-by-step explanation:

4 0
2 years ago
ms rivera went to the store and spent $10.00 on apples. apples are on sale for $2.00 per pound. how many pounds did ms rivera bu
MaRussiya [10]

Answer:

She bought 5 pounds.

Step-by-step explanation:

if she spent 10 dollars and its 2 dollars per pound that means that you have to divide 10 by 2 in order to get how many pounds you can buy for 10 dollars.

If you think about it if you want 2 pounds then you multiply 2 by 2 to get four because its 2 dollars per pound and you need 2 pounds. so since you don't know the number of pounds you fill in the blanks and do 10/2 to get 5.

4 0
2 years ago
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Consider the differential equation x2y′′ − 9xy′ + 24y = 0; x4, x6, (0, [infinity]). Verify that the given functions form a funda
pantera1 [17]

Answer:

The functions satisfy the differential equation and linearly independent since W(x)≠0

Therefore the general solution is

y= c_1x^4+c_2x^6

Step-by-step explanation:

Given equation is

x^2y'' - 9xy+24y=0

This Euler Cauchy type differential equation.

So, we can let

y=x^m

Differentiate with respect to x

y'= mx^{m-1}

Again differentiate with respect to x

y''= m(m-1)x^{m-2}

Putting the value of y, y' and y'' in the differential equation

x^2m(m-1) x^{m-2} - 9 x m x^{m-1}+24x^m=0

\Rightarrow m(m-1)x^m-9mx^m+24x^m=0

\Rightarrow m^2-m-9m+24=0

⇒m²-10m +24=0

⇒m²-6m -4m+24=0

⇒m(m-6)-4(m-6)=0

⇒(m-6)(m-4)=0

⇒m = 6,4

Therefore the auxiliary equation has two distinct and unequal root.

The general solution of this equation is

y_1(x)=x^4

and

y_2(x)=x^6

First we compute the Wronskian

W(x)= \left|\begin{array}{cc}y_1(x)&y_2(x)\\y'_1(x)&y'_2(x)\end{array}\right|

         = \left|\begin{array}{cc}x^4&x^6\\4x^3&6x^5\end{array}\right|

         =x⁴×6x⁵- x⁶×4x³    

        =6x⁹-4x⁹

        =2x⁹

       ≠0

The functions satisfy the differential equation and linearly independent since W(x)≠0

Therefore the general solution is

y= c_1x^4+c_2x^6

5 0
3 years ago
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