128 = a + + 4(a + 10) + (a + 10)
128 = a + 4a + 40 + a + 10
128 = 6a + 50
128-50 = 6a
78 = 6a
13 = a
1st = a = 13
2nd = 4(a + 10) = 4(23) = 92
3rd = a + 10 = 23
Answer:H)
Step-by-step explanation:
have a nice day
Try to refrain from asking more than three questions per question for future reference.
11+4=15
6+4=10
4+7=11
12+4=16
0+4=4
4+0=4
10+4=14
4+5=9
9+4=13
4+2=6
4+8=12
4+3=7
7+4=11
4+4=8
4+1=5
8+4=12
Hope this helps.
-Benjamin
X^2+4x+4 and there is no remainder
It is not. In the decimal system each column to the right is valued at powers of ten starting at zero and increasing as you move to the left...in a four digit number...the columns are valued at...
10^3, 10^2, 10^1, 10^0 which corresponds to...
1000, 1000, 10, 1 in this case the first digit is equal to
5(1000)=5000 the value of the last digit is 5(1)=5
So the first 5 is 1000 times as great as the second 5...
Hope this helps!
