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schepotkina [342]
3 years ago
9

How do I solve this problem?

Mathematics
2 answers:
bulgar [2K]3 years ago
6 0

Answer:

3\frac{4}{8} cups

Step-by-step explanation:

<u>To subtract two fractions with different denominators easily, you can find the LCM of the denominators to make a simple subtraction problem.</u>

LCM - <em>Lowest Common Multiple</em>

<u>To find the LCM of two numbers, write down each numbers' times tables until they have a common number:</u>

4 - 4, 8, 12, 16, 20,....

8 - 8, 16, 24, 32, 40,....

Because 8 is the first number to be in both numbers' multiples, it is the LCM of 4 and 8.

<u>Now that the LCM has been determined, you need both denominators to be 8. This is an easy process as it is simple multiplication:</u>

3 \frac{1}{4} → \frac{1}{4} × \frac{2}{2} = \frac{2}{8}

6 \frac{6}{8} → no multiplication needed.

<u>Now to subtract:</u>

6 \frac{6}{8} - 3 \frac{2}{8} = 3 \frac{4}{8}

Because the question does not want a simplified fraction, the final answer is 3 \frac{4}{8} cups.

romanna [79]3 years ago
3 0

Answer:

It will be 3 4/8 or 3 1/2

<u><em>PLS MARK BRAINLIEST</em></u>

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