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3 years ago

How do I solve this problem?

Mathematics

2 answers:

bulgar [2K]3 years ago

6 0

Answer:

3 $\frac{4}{8}$ cups

Step-by-step explanation:

To subtract two fractions with different denominators easily, you can find the LCM of the denominators to make a simple subtraction problem.

LCM - Lowest Common Multiple

To find the LCM of two numbers, write down each numbers' times tables until they have a common number:

4 - 4, 8, 12, 16, 20,....

8 - 8, 16, 24, 32, 40,....

Because 8 is the first number to be in both numbers' multiples, it is the LCM of 4 and 8.

Now that the LCM has been determined, you need both denominators to be 8. This is an easy process as it is simple multiplication:

3 $\frac{1}{4}$ → $\frac{1}{4}$ × $\frac{2}{2}$ = $\frac{2}{8}$

6 $\frac{6}{8}$ → no multiplication needed.

Now to subtract:

6 $\frac{6}{8}$ - 3 $\frac{2}{8}$ = 3 $\frac{4}{8}$

Because the question does not want a simplified fraction, the final answer is 3 $\frac{4}{8}$ cups.

romanna [79]3 years ago

3 0

Answer:

It will be 3 4/8 or 3 1/2

PLS MARK BRAINLIEST

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$y-y_o=m(x-x_o)$

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