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Reika [66]
3 years ago
11

May I Please Get Help With Questions 2 and 4

Mathematics
1 answer:
kotegsom [21]3 years ago
8 0

Answer:

22 and 31

Step-by-step explanation:

from the table we know that f(0) = 22 and f(-3) = 31

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Graph the linear equation y=-1/5x+3​
adoni [48]

Answer:

ur answer is a

4 0
3 years ago
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The sum of a number xx and 4 equals 12. an equation that represents this sentence is
lora16 [44]
X + 4 = 12

This is because the question gives you everything you require for this sentence to be formed. 12 is the final answer. 4 is added on and x is basically the number that is to be found.
5 0
3 years ago
You own an accessories store, and sales last month were $24,000. You had $3,500 in discounts and $975 in returns.
Len [333]

Answer:

The net sales for last month were <u>$19,525</u>.

Step-by-step explanation:

Given:

Last month sales were $24,000.

Discounts is $3,500 and $975 in returns.

Now, to get the net sales for last month.

So, we deduct the discount:

<em>Sales - discounts</em> = \$24,000 - \$3,500 =\$20,500.

Then, we deduct the returns from the remaining amount:

<em>Sales after discounts - returns</em> = \$20,500 - \$975

                                                   = \$19,525.

Therefore, the net sales for last month were $19,525.

7 0
3 years ago
5x + 10 = 20
Andrei [34K]

To solve for <em>x</em>, we must first isolate the term containing <em>x</em> which in this problem is 5x.

Since 10 is being added to 5x, we subtract 10 from both sides of the equation to isolate the 5x.

On the left, the +10 and -10 cancel out and on the right, 20 - 10 is 10 and we have 5x = 10.

Now we can finish things off by just dividing both sides of the equation by 5. On the left the 5's cancel and on the right, 10 divided by 5 is 2 so <em>x = 2</em>.

4 0
3 years ago
Explain how modeling partial products can be used to find the products of greater numbers ?
liq [111]

You can break large numbers into a sum of a multiple(s) of 10 and the last digit of the number. For example, you can break 26 as 20+6, or 157 as 100+50+7.

Then, using the distributive property, you can turn the original multiplication into a sum of easier multiplications. For example, suppose we want to multiply 26 and 37. This is quite challenging to do in your mind, but you can break the numbers as we said above:

26\times 37=(20+6)(30+7) = 20\times 30+20\times 7+30\times 6+6\times 7

All these multiplications are rather easy, because they either involve multiples of 10 of single-digit numbers:

20\times 30+20\times 7+30\times 6+6\times 7 = 600+140+180+42=962

3 0
3 years ago
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