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2 years ago

Find the values of x and y if (2x + y, 2) = (1, x - y).

4 answers:

7 0

Use elimination

2x + y = 1
+ (x - y = 2)

3x=3

X=1. Plug back into one of the equations.

1-y=2. Isolate y.

Y=-1

The Answer is (1,-1)

m_a_m_a [10]2 years ago

6 0

Answer:

We have, 2x+y=3 .......(1)

xy=1....(2)

In equation (2), we get

..........(3)

y put in the equation (1)

2x+

+1=3x

−3x+1=0

−3x−1x+1=0

2x(x−1)−1(x−1)=0

x=1, x=

We take the value of x=1

x value put in equation (1)

2(1)+y=3

y=3−2

y=1

x=1

x and y value put (x+y)

x−y

=(1+1)

(1−1)

Hence, this is the answer

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Rukia Kuchiki2 years ago

0 0

>hello< IM SOOO BOOOOORRRRREEEEEEEDDDDDDDDD, also, I wouldsolve ur question but its 6:30am where I live

Bipper Pinetree2 years ago

0 0

your mom

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prohojiy [21]

d₁ = -16t² + 122t

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d = d₁ - d₂

d = -16t² + 122t - (-16t² + 84t)

d = 38t

After five seconds, t=5,

d = 38(5) = 190

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3 years ago

I don’t know how to solve this

LuckyWell [14K]

Answer:

(3x-5)x(3x+5)

Step-by-step explanation:

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3 years ago

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Troyanec [42]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\

\begin{array}{rllll} 
% left side templates
f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}
\end{array}$

$\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\end{array}$

$\bf \begin{array}{llll}


\bullet \textit{ vertical shift by }{{ D}}\\
\qquad if\ {{ D}}\textit{ is negative, downwards}\\\\
\qquad if\ {{ D}}\textit{ is positive, upwards}\\\\
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\end{array}$

now, with that template in mind, let's take a peek at this function

$\bf \begin{array}{lllcclll}
y=&2(&1x&-2)^2&-4\\
&\uparrow &\uparrow &\uparrow &\uparrow \\
&A&B&C&D
\end{array}\\\\
-----------------------------\\\\
A\cdot B=2\impliedby \textit{shrunk by a factor of 2, of half-size}\\\\
\cfrac{C}{B}= \cfrac{-2}{1}\implies -2\impliedby \textit{horizontal right shift of 2 units}\\\\
D=-4\impliedby \textit{vertical down shift of 4 units}$

so, the graph of y=2(x-2)²-4, is really the same graph of y=x², BUT, narrower, and moved about horizontally and vertically

8 0

3 years ago

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DanielleElmas [232]

Answer:6

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Step-by-step explanation:

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3 years ago

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Boston, Massachusetts had a population of 617,594 people during January 1 2010, and 675,647 people on January 1 2020.

tigry1 [53]

Answer:

See below

Step-by-step explanation:

Exponential function is:

y = abˣ

If we consider the time difference in years as x and the initial population as a, then we get:

675647 = 617594*b¹⁰

Find the value of b:

b¹⁰ = 675647/617594
b¹⁰ = 1.09399864636
b = 1.09399864636^(1/10)
b = 1.009 (rounded)

The equation we got is:

y = 617594*1.009ˣ

Here we have y- population after x years since 2010, x - the number of years since 2010 and 1.009 is the population growth rate.

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2 years ago

Find the values of x and y if (2x + y, 2) = (1, x - y). ​

Find the values of x and y if (2x + y, 2) = (1, x - y).