The height of the water tower is found to be 54.66 meters.
<h3>What is acceleration due to gravity?</h3>
A free-falling object is one that is falling solely due to gravity.
Some key features regarding the acceleration due to gravity are-
- A free-falling component has a downward acceleration of 9.8 m/s/s (on Earth).
- This magnitude for the acceleration of a free-falling object is so significant that it has its own name.
- The acceleration of gravity is the acceleration of any object moving solely under the influence of gravity.
- In fact, the acceleration of gravity is so important quantity that scientists have a special symbol to represent it - the symbol g.
- The most precise numerical value for gravity's acceleration is 9.8 m/s/s.
Now, according to the question;
It takes a watermelon 3.34 sec to reach the ground.
Use the equation of motion in straight line.
D = (1/2) x (gravity) x (time)²
D is the height of the water tower.
= (1/2) x (9.8 m/s²) x (3.34 sec)²
= (4.9 m/s²) x (11.16 sec²)
D = 54.66 meters.
Thus, the height of the water tower is estimated as 54.66 meters.
To know more about acceleration due to gravity, here
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Pink and yellow are perpendicular
Answer:
Well there is no linear equation that represents y as a function of x. You said it yourself, "The data CANNOT be modeled by a linear equation because the rate of change is not constant."
Step-by-step explanation:
There is none. y has random values.
Answer:
C. 30
Step-by-step explanation:
circumference of the semicircular plot
![=\frac{1}{2}\times\pi d+d\\\\=\frac{1}{2}\times 3.14\times 35+ 35\\\\= \frac{1}{2}\times 109.9+35\\\\= 54.95+35\\\\= 89.95\\\\No. \: of\: poles= \frac{89.95}{3}\\\\= 29.98\\\\\approx 30](https://tex.z-dn.net/?f=%3D%5Cfrac%7B1%7D%7B2%7D%5Ctimes%5Cpi%20d%2Bd%5C%5C%5C%5C%3D%5Cfrac%7B1%7D%7B2%7D%5Ctimes%203.14%5Ctimes%2035%2B%2035%5C%5C%5C%5C%3D%20%5Cfrac%7B1%7D%7B2%7D%5Ctimes%20109.9%2B35%5C%5C%5C%5C%3D%2054.95%2B35%5C%5C%5C%5C%3D%2089.95%5C%5C%5C%5CNo.%20%5C%3A%20of%5C%3A%20poles%3D%20%5Cfrac%7B89.95%7D%7B3%7D%5C%5C%5C%5C%3D%2029.98%5C%5C%5C%5C%5Capprox%2030)
Answer:
Given the statement: Kite QRST has a short diagonal of QS and a long diagonal of RT. The diagonals intersect at point P.
Properties of Kite:
- The diagonals are perpendicular
- Two disjoint pairs of consecutive sides are congruent by definition of kite
- One diagonal is the perpendicular bisector to the other diagonal.
It is given that: Side QR = 5m and diagonal QS = 6m.
Then, by properties of kite:
![QP = \frac{1}{2}QS](https://tex.z-dn.net/?f=QP%20%3D%20%5Cfrac%7B1%7D%7B2%7DQS)
Substitute the value of QS we get QP;
= 3 m
Now, in right angle ![\triangle RPQ](https://tex.z-dn.net/?f=%5Ctriangle%20RPQ)
Using Pythagoras theorem:
![QR^2= RP^2 +QP^2](https://tex.z-dn.net/?f=QR%5E2%3D%20RP%5E2%20%2BQP%5E2)
Substitute the given values we get;
![(5)^2= RP^2 +(3)^2](https://tex.z-dn.net/?f=%285%29%5E2%3D%20RP%5E2%20%2B%283%29%5E2)
or
![25= RP^2 +9](https://tex.z-dn.net/?f=25%3D%20RP%5E2%20%2B9)
Subtract 9 from both sides we get;
![16= RP^2](https://tex.z-dn.net/?f=16%3D%20RP%5E2)
Simplify:
![RP = \sqrt{16} = 4 m](https://tex.z-dn.net/?f=RP%20%3D%20%5Csqrt%7B16%7D%20%3D%204%20m)
Therefore, the length of segment RP is, 4m