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2 years ago

10

5*10^1 in standard form

1 answer:

elixir [45]2 years ago

7 0

Answer:

50

Step-by-step explanation:

5 times ten to the power of 1 would be = 50

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Integrate this two questions

tankabanditka [31]

Simplify the integrands by polynomial division.

$\dfrac{t^2}{1 - 3t} = -\dfrac19 \left(3t + 1 - \dfrac1{1 - 3t}\right)$

$\dfrac t{1 + 4t} = \dfrac14 \left(1 - \dfrac1{1 + 4t}\right)$

Now computing the integrals is trivial.

5.

$\displaystyle \int \frac{t^2}{1 - 3t} \, dt = -\frac19 \int \left(3t + 1 - \frac1{1-3t}\right) \, dt \\\\ = -\frac19 \left(\frac32 t^2 + t + \frac13 \ln|1 - 3t|\right) + C \\\\ = \boxed{-\frac{t^2}6 - \frac t9 - \frac{\ln|1-3t|}{27} + C}$

where we use the power rule,

$\displaystyle \int x^n \, dx = \frac{x^{n+1}}{n+1} + C ~~~~ (n\neq-1)$

and a substitution to integrate the last term,

$\displaystyle \int \frac{dt}{1-3t} = -\frac13 \int \frac{du}u \\\\ = -\frac13 \ln|u| + C \\\\ = -\frac13 \ln|1-3t| + C ~~~ (u=1-3t \text{ and } du = -3\,dt)$

8.

$\displaystyle \int \frac t{1+4t} \, dt = \frac14 \int \left(1 - \frac1{1+4t}\right) \, dt \\\\ = \frac14 \left(t - \frac14 \ln|1 + 4t|\right) + C \\\\ = \boxed{\frac t4 - \frac{\ln|1+4t|}{16} + C}$

using the same approach as above.

5 0

1 year ago

Which is 625 written as a power of 5 (exponets) A. 4*5 B.3*5 C.5*3 D.5*4

OleMash [197]

<span>625 written as a power of 5 = 5^4
because
5^4 = (5) * (5) *(5) * (5) =625

answer is
</span><span>D.5^4</span>

8 0

3 years ago

Read 2 more answers

A watercolor painting is 24 inches long by 11 inches wide. Ramon makes a border around the watercolor painting by making a mat t

sergeinik [125]

Given: It is given that the length of the painting is 24 inches and the width is 11 inches.

To find: Area of the mat

Solution:

The watercolor painting is 24 inches long by 11 inches wide.

So, the area of the painting is:

$\text{Area of painting}=l\times b$

$\text{Area of painting}=24\times 11$

$\text{Area of painting}=264 \text{ in}^2$

The length of painting with mat is = 24 in + 3 in + 3 in = 30 in

The width of painting with mat = 11 in + 3 in + 3 in = 17 in

$\text{Area of painting with mat}=30\times 17$

$\text{Area of painting with mat}=510 \text{ in}^2$

Now to calculate the area of mat subtracts the area of painting from the area of the mat.

$\text{Area of mat}=\text{Area of painting with mat}-\text{Area of painting}\\$

$\text{Area of mat}=510-264$

$\text{Area of mat}=246 \text{ in}^2$

Hence, the area of the mat is 246 in².

6 0

2 years ago

State the reason why >K = >M<br><br> KLMN is a parallelogram.

Semmy [17]

The opposite angles of a parallelogram are equal. Therefore, for parallelogram KLMN, <K = <M

3 0

3 years ago

What is the slope of this equation: y = -5x + 4

tekilochka [14]

Answer:

Slope = -5

Step-by-step explanation:

5 0

2 years ago