The number of integer values of n for which the value 4000 × (0.4)ⁿ is an integer is; 9
<h3>How to find the integer values in algebra?</h3>
We are given the expression;
4000 × (0.4)ⁿ
This can also be expressed as;
4000 × (²/₅)ⁿ which can further be expressed in exponent form as;
(2⁵ × 5³) × (²/₅)ⁿ = 2⁽⁵ ⁺ ⁿ⁾ × 5⁽³ ⁻ ⁿ⁾
Since this expression is an integer, we need:
1) 5 + n ≥ 0 for which n ≥ -5
2) 3 - n ≥ 0 for which n ≤ 3
Taking the intersection gives;
-5 ≤ n ≤ 3
Thus;
Number of Integer Values = 3 - (-5) + 1 = 9
Read more about Integer Values at; brainly.com/question/17695139
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Answer:6
Step-by-step explanation:
when x is -1 y is 6. input -1 as x in the equation and solve, otherwise graph.
Answer:
p-value = P(z < -1.5713) = 0.0581
Conclusion: Since the p-value is greater than 5%,
fail to reject.
The test results to not support the claim
Step-by-step explanation:
Step-by-step explanation:
to find his total expenses, add all fraction spent
3/8 + 1/3 + 1/6
= 9+8+ 4/24
= 21/24. = 7/8
total fraction =1
subtract the fraction spent form the total fraction to know the fraction left for savings
1-7/8= 1/8
therefore if. 1 = 2,400
then 1/8=?
if less more divides
1/8 ÷ 1 ×2,400
1/8 × 1/1×2,400
1/8 × 2,400
=300.
therefore the man saved 300 rupees
