Help pleaseh - (-2) ≥ 10
1 answer:
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Answer:
Given :- ABCD is a square.
To proof :- AC = BD and AC ⊥ BD
Proof :- In △ ADB and △ BCA
AD = BC [ Sides of a square are equal ]
∠BAD = ∠ABC [ 90° each ]
AB = BA [ Common side ]
△ADB ≅ △BCA [ SAS congruency rule ]
⇒ AC = BD [ Corresponding parts of congruent triangles are equal ]
In △AOB and △AOD
OB = OD [ Square is also a parallelogram therefore, diagonal of parallelogram bisect each other ]
AB = AD [ Sides of a square are equal ]
AO = AO [ Common side ]
△AOB ≅ △ AOD [ SSS congruency rule ]
⇒ ∠AOB = ∠AOD [ Corresponding parts of congruent triangles are equal]
∠AOB + ∠AOD = 180° [ Linear pair ]
∠ AOB = ∠AOD = 90°
⇒ AO ⊥ BD
⇒ AC ⊥ BD
Hence proved, AC = BD and AC ⊥BD
Answer:
The median of the distribution is (first option);
1
Step-by-step explanation:
The values on the given table are presented as follows;
To find the median, we calculate the cumulative probabilities to find the value of the spin art which the cumulative probability is 0.5 as follows;
Cumulative probability, starting from the left, is therefore;
Probability for spin of 0, 0.4 + Probability for spin of 1, 0.2 = 0.6
Therefore, given that the probability of 0.5 occurs within the Value of Spin 1, the median of the probability distribution is 1