Question

What is the solution?="TexFormula1" title="\lim_{x\to 0} \frac{x + 2}{ x -2}" alt="\lim_{x\to 0} \frac{x + 2}{ x -2}" align="absmiddle" class="latex-formula">
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Math please ​​

Answer 1

Answer:

- 1

Ok? Understand?

........

Answer 2

Answer:

$- 1$

Step-by-step explanation:

$\lim_{x\to 0} \frac{x + 2}{ x -2}$

$= \frac{0 + 2}{ 0 -2}$

$= \frac{2}{-2}$

$= - 1$