Purple and white make up less than 30 %
<span>There are 4 vans. So we have that probability that the first vehicle is a van p (e) = 4/10 = 0.4.
P(e|f) = P( f and e) / p (f)
p(e) = 0.4 and p(f) = 3/9
P (f and e) = 0.40 * 0.33 = 0.132
So p(e|f) = 0.4 * 0.33/ 0.33 = 0.4
P(f and e) p(f) * p(e) = 0.4 * 0.33 = 0.132</span>
2/17 is the lowest term for 6/51
