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3 years ago

Find the 84th percentile

Mathematics

1 answer:

morpeh [17]3 years ago

5 0

Answer:

Roughly speaking, in a normal distribution, a score that is 1 s.d. above the mean is equivalent to the 84th percentile. ... In other words, roughly 95 percent of students are within two standard deviations – positive or negative – of the average

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The length width and height of a rectangular solid are 8,4,1 respectively what is the length of the longest line segment whose e

LUCKY_DIMON [66]

Answer:

9 units

Step-by-step explanation:

Given

$Length = 8$

$Width = 4$

$Height = 1$

Required

Determine the length of the longest segment

To do this, we use:

$Longest = \sqrt{Length^2 + Width^2 + Height^2}$

So, we have:

$Longest = \sqrt{8^2 + 4^2 + 1^2}$

$Longest = \sqrt{64 + 16 + 1}$

$Longest = \sqrt{81}$

Take positive square root

$Longest = 9$

Hence, the length of the longest segment is 9 units

3 0

3 years ago

Ella swims four times a week at her clubs pool. She swims the same number of laps on Monday,Wednesday,Friday,and 15 laps on Satu

Reika [66]

She swims 12 laps on Monday.

Step-by-step explanation:

Total laps = 51 laps

Laps on Saturday = 15 laps

Let,

x be the number of laps on Monday, Wednesday and Friday each.

According to given statement;

Monday+Wednesday+Friday+Saturday = 51

$x+x+x+15=51\\3x=51-15\\3x=36$

Dividing both sides by 3

$\frac{3x}{3}=\frac{36}{3}\\x=12$

She swims 12 laps on Monday.

Keywords: addition, division

Learn more about division at:

#LearnwithBrainly

7 0

3 years ago

What is (10/3) squared?

saveliy_v [14]

(10/3)^2 = 10^2/3^2 = 100/9= 11.1

6 0

3 years ago

Read 2 more answers

Find the possible values of x. the perimeter is less than or equal to 51 meters.

sertanlavr [38]

Answer-

The value of x can be anything between 0 to 15

Solution-

Perimeter of a geometrical figure is the sum of lengths of all its sides.

So, the value of the perimeter of the given pentagon would be,

$=8+8+10+10+x\\\\=(36+x)\ meters$

As given in the question that, the perimeter is less than or equal to 51 meters.

So,

$\Rightarrow 36+x\leq 51$

$\Rightarrow x\leq 15$

As the side length can not be negative, so x must be positive, i.e

$0$

5 0

3 years ago

If a car travels 10 ft due north and then 15 feet due west, how far is the car from it starting point? This is for homework and

krok68 [10]

Answer:

Explanation:

The car travel 10ft north then 15ft due west. In order to find the distance from starting point. We need to find the hypotenuse where the distance to north and west are the adjacent side.

We can use Pythagorean’s theorem according to that:

Let c be the distance from starting point.
And a and b be the distance travel to north and west.

a^2 + b^2 = c^2
10^2 + 15^2 = c^2
100 + 225 = c^2
325 = c^2
Sqrt(325) = c
5sqrt(13) = c

Therefore, the distance from starting point is 5sqrt(13) ft

5 0

4 years ago