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Darina [25.2K]
3 years ago
7

Identify the range of the function shown in the graph.

Mathematics
2 answers:
creativ13 [48]3 years ago
5 0
B. I believe I just wanna get some points
kiruha [24]3 years ago
3 0

Answer:

B

Step-by-step explanation:

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The product of the square of a number x and 2 subtracted from 3 is y.
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The algebraic expression for the given statement is: 2x² - 3 = y.

<h3>How to Write an Algebraic Expression?</h3>

To wrote an algebraic expression is translate a statement using numbers, variables, and mathematical sign into a mathematical statement.

Square of x is: x²

Product of x² and 2 is: 2x²

Thus, we would have:

2x² - 3 = y

The algebraic expression is: 2x² - 3 = y.

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Describe the error Sarah made when simplifying the expression shown. -5(x-2)=-5x-10
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I think that's what you mean

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Money Flow  The rate of a continuous money flow starts at $1000 and increases exponentially at 5% per year for 4 years. Find the
77julia77 [94]

Answer:

Present value =  $4,122.4

Accumulated amount = $4,742

Step-by-step explanation:

Data provided in the question:

Amount at the Start of money flow = $1,000

Increase in amount is exponentially at the rate of 5% per year

Time = 4 years

Interest rate = 3.5%  compounded continuously

Now,

Accumulated Value of the money flow = 1000e^{0.05t}

The present value of the money flow = \int\limits^4_0 {1000e^{0.05t}(e^{-0.035t})} \, dt

= 1000\int\limits^4_0 {e^{0.015t}} \, dt

= 1000\left [\frac{e^{0.015t}}{0.015} \right ]_0^4

= 1000\times\left [\frac{e^{0.015(4)}}{0.015} -\frac{e^{0.015(0)}}{0.015} \right]

= 1000 × [70.7891 - 66.6667]

= $4,122.4

Accumulated interest = e^{rt}\int\limits^4_0 {1000e^{0.05t}(e^{-0.035t}} \, dt

= e^{0.035\times4}\times4,122.4

= $4,742

8 0
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