$(2x^2-3x+4) ( x^2+5x-7)= \\ \\=2x^2*x^2+2x^2*5x-2x^2*7-3x*x^2-3x*5x+3x*7+4*x^2+4*5x-4*7=\\ \\=2x^4+10x^3-14x^2 -3 x^3-15x^2+21x +4 x^2+20x-28=\\ \\=2x^4+7x^3-25x^2 +41x -28$

3 0

3 years ago

What is the approximate radius of a sphere with a volume of 1436cm to power of 3

Margarita [4]

Answer:

<h3>The radius is 7 cm</h3>

Step-by-step explanation:

Volume of a sphere is given by

$V = \frac{4}{3} \pi {r}^{3}$

where r is the radius

From the question V = 1436 cm³

$1436 = \frac{4}{3} \pi {r}^{3}$

Multiply through by 3

We have

$4308 = 4\pi {r}^{3}$

Divide both sides by 4π

${r}^{3} = \frac{4308}{4\pi}$

${r}^{ 3} = \frac{1077}{\pi}$

Find the cube root of both sides

$r = \sqrt[3]{ \frac{1077}{\pi} }$

r = 6.99

We have the final answer as

Hope this helps

3 0

3 years ago

Compare using < or > or =<br><br><br> -15____-21

Salsk061 [2.6K]

<h3><u><em>Answer:</em></u></h3>

-15 > -21

We know that 15 < 21 then -15 > -21

5 0

3 years ago