Answer:
Step-by-step explanation:
- 2· + 20 = 32
- 2· = 12
- = 6
- (v + 4) log 4 = log 6
- v + 4 = log 6 / log 4
- v + 4 = 1.29 (<em>rounded</em>)
- v = 1.29 - 4
- v = - 2.71
Given:
The bases of triangular prism are right triangles with a base of 12 inches and height of 9 inches.
The height of the prism is 11 inches.
To find:
The surface area of the triangular prism.
Solution:
Using the Pythagoras theorem, the hypotenuse of the bases of the triangular prism is:
Taking square root on both sides.
The surface after of the triangular prism contains 3 rectangles of dimensions 12 inches by 11 inches, 9 inches by 11 inches, 15 inches by 11 inches and two triangles with base 12 inches and height 9 inches.
Area of the rectangle:
So, the area of three rectangles are:
Area of a triangle is:
So, the area of the triangles is:
And, the triangles have same dimensions so their areas are equal.
Now,
Therefore, the surface area of the triangular prism is 504 sq. inches.
Total = principal * (1 + rate) ^ years
Solving for principal:
principal = total / [(1 + rate) ^ years]
principal = 30,000 / (1.05)^10
principal = 30,000 /
<span>
<span>
<span>
1.6288946268
</span>
</span>
</span>
principal =
<span>
<span>
<span>
18,417.</span></span></span>40
Answer:
50/20
Step-by-step explanation: