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Ad libitum [116K]
3 years ago
13

Trensie is flipping a weighted coin where the probability of landing on tails is 1/ 3 . If she flips the coin two times, what is

the probability that she gets heads only once?
Mathematics
1 answer:
fomenos3 years ago
4 0
The total possibilities is still 4.
H H
H T <<<< 
T H <<<<
T T

The two that work are marked with <<<<

H T = 1/3 * 2/3 = 2/9
T H = 2/3 * 1/3 = 2/9



The total is 2/9 + 2/9 = 4/9
We should check this
1 heads = 4/9
2 heads = 1/9
2 tails = 4/9
4/9 + 4/9 + 1/9 = 1 It checks 
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Robert and Freddie like to go to the library in their town to borrow books. Robert goes to the library every 9 days and Freddie
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Answer: 36 days

Step-by-step explanation:

that’s the lowest multiple of 9 that also is a multiple of 12. It’s the LCF aka Least Common Factor

3 0
2 years ago
Quadratic equations are never used to solve word problems. True or false?
mel-nik [20]
Quadratic equations CAN be used to solve word problems so the answer to your question is false
7 0
3 years ago
HOW do you find the value of TAN 88 degrees 22' 45'' and COT 36 degrees???
storchak [24]
Part 1
We want to find the tan of 88 degrees, 22' 45''.

88° 22' 45''
= 88 + 22/60 + 45/3600 degrees
= 88.3792°

From the calculator, obtain
tan(88.3792°) = 35.3409

Answer: 35.3409

Part 2
We want to find cot(36°).

By definition, cot(x) = 1/tan(x).
From the calculator, obtain
tan(36°) = 0.7265
Therefore
cot(36°) = 1/0.7265 = 1.3764

Answer: 1.3764

3 0
4 years ago
A drug is eliminated from the body through urine. Suppose that for a dose of 10 milligrams, the amount A(t) remaining in the bod
adell [148]

Answer: a - 4.512 hours

b - 1.94 hours

Step-by-step explanation:

Given,

a) A(t) = 10 (0.7)^t

To determine when 2mg is left in the body

We would have,

A(t) = 2, therefore

2 = 10(0.7)^t

0.7^t =2÷10

0.7^t = 0.2

Take the log of both sides,

Log (0.7)^t = log 0.2

t log 0.7 = log 0.2

t = log 0.2/ 0.7

t = 4.512 hours

Thus it will take 4.512 hours for 2mg to be left in the body.

b) Half life

Let A(t) = 1/2 A(0)

Thus,

1/2 A(0) = A(0)0.7^t

Divide both sides by A(0)

1/2 = 0.7^t

0.7^t = 0.5

Take log of both sides

Log 0.7^t = log 0.5

t log 0.7 = log 0.5

t = log 0.5/log 0.7

t = 1.94 hours

Therefore, the half life of the drug is 1.94 hours

6 0
3 years ago
Which is the best estimate of 162% of 79? O 112 O 119 O 128 O 136​
sladkih [1.3K]

Answer:

128

Step-by-step explanation:

You would multiply 79 by 1.62 to get the answer.

This would give you 127.98 which you would round up to 128.

4 0
3 years ago
Read 2 more answers
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