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Leona [35]
3 years ago
13

Simplify this complex fraction .

Mathematics
2 answers:
In-s [12.5K]3 years ago
8 0
Simplified complex fraction: 1/21
Harlamova29_29 [7]3 years ago
5 0
The simplified complex fraction would be 1/21
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Carlos is using a number line to add another integer to –4. He begins by showing –4 on the number line, as shown below. Carlos a
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The number must be a negative integer because -4+ any negative is a negative

Step-by-step explanation:

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The point-slope form of the equation of the line that passes through (-4,-3) and (12,1) is y-1=1/4(x-12). What is the standard f
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Multiply by 4 and rearrange.

... 4y -4 = x - 12

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In the LifeSmarts event, students compete
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Step-by-step explanation:

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An elevator has a placard stating that the maximum capacity is 1600 lb�10 passengers.​ So, 10 adult male passengers can have a m
Bezzdna [24]

Answer:

1. 0.7421 = 74.21% probability the elevator is overloaded.

2. D.​No, there is a good chance that 10 randomly selected people will exceed the elevator capacity.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Assume that weights of males are normally distributed with a mean of 166 lb and a standard deviation of 29 lb​.

This means that \mu = 166, \sigma = 29

Sample of 10.

This means that n = 10, s = \frac{29}{\sqrt{10}}

1.The probability the elevator is overloaded is?

Probability that the sample mean is above 160 pounds, which is 1 subtracted by the p-value of Z when X = 160. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{160 - 166}{\frac{29}{\sqrt{10}}}

Z = -0.65

Z = -0.65 has a p-value of 0.2579.

1 - 0.2579 = 0.7421

0.7421 = 74.21% probability the elevator is overloaded.

2. Does this elevator appear to be​ safe?

High probability of the elevator being overloaded, so not safe. Correct answer is given by option D.

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3 years ago
two number cubes are rolled what is the probability of rolling a number greater then four on each number cube
miss Akunina [59]
4 out of 12
so 1 out of 3
3 0
3 years ago
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