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Eddi Din [679]
3 years ago
15

49/63 reduced fraction

Mathematics
2 answers:
statuscvo [17]3 years ago
5 0
To reduce a fraction, you must find what number goes into both the numerator and denominator evenly.

In this case, 7 goes into each number evenly.

All we need to do now is divide each number by 7.

49\div7=7\\63\div7=9\\\\\frac{7}{9}


marin [14]3 years ago
3 0
49 / 7 = 7
63 / 7 = 9,
You place 7 over 9 and you get your answer!

7/9
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Parallel lines have the same slope. The slope of y = -1/3 x + 4 is -1/3.

The equation is

(y - 5) = -1/3 (x - 6)

y = -1/3 x -1/3 (- 6) + 5 = -1/3 x + 2 + 5 = -1/3 + 7

The equation is: y = - 1/3 x + 7

y = -1/3 x
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Step-by-step explanation:

If x=1 and y=22 then y=22x

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So I would say your answer is..............A

Step-by-step explanation:

For most places, global warming will result in more frequent hot days and fewer cool days, with the greatest warming occurring over land. Longer, more intense heat waves will become more common. Storms, floods, and droughts will generally be more severe as precipitation patterns change

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Evaluate x ➗ y, if x = 29.665 and y = 6.98
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Step-by-step explanation:

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3 years ago
The Department of Agriculture is monitoring the spread of mice by placing 100 mice at the start of the project. The population,
uranmaximum [27]

Answer:

Step-by-step explanation:

Assuming that the differential equation is

\frac{dP}{dt} = 0.04P\left(1-\frac{P}{500}\right).

We need to solve it and obtain an expression for P(t) in order to complete the exercise.

First of all, this is an example of the logistic equation, which has the general form

\frac{dP}{dt} = kP\left(1-\frac{P}{K}\right).

In order to make the calculation easier we are going to solve the general equation, and later substitute the values of the constants, notice that k=0.04 and K=500 and the initial condition P(0)=100.

Notice that this equation is separable, then

\frac{dP}{P(1-P/K)} = kdt.

Now, intagrating in both sides of the equation

\int\frac{dP}{P(1-P/K)} = \int kdt = kt +C.

In order to calculate the integral in the left hand side we make a partial fraction decomposition:

\frac{1}{P(1-P/K)} = \frac{1}{P} - \frac{1}{K-P}.

So,

\int\frac{dP}{P(1-P/K)} = \ln|P| - \ln|K-P| = \ln\left| \frac{P}{K-P} \right| = -\ln\left| \frac{K-P}{P} \right|.

We have obtained that:

-\ln\left| \frac{K-P}{P}\right| = kt +C

which is equivalent to

\ln\left| \frac{K-P}{P}\right|= -kt -C

Taking exponentials in both hands:

\left| \frac{K-P}{P}\right| = e^{-kt -C}

Hence,

\frac{K-P(t)}{P(t)} = Ae^{-kt}.

The next step is to substitute the given values in the statement of the problem:

\frac{500-P(t)}{P(t)} = Ae^{-0.04t}.

We calculate the value of A using the initial condition P(0)=100, substituting t=0:

\frac{500-100}{100} = A} and A=4.

So,

\frac{500-P(t)}{P(t)} = 4e^{-0.04t}.

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\frac{500-200}{200} = 4e^{-0.04t}.

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So, the population of rats will be 200 after 25 months.

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