From the question, we know that we will be looking at <3, <4, and angles TKL and TLK. That being said, since <3 is congruent to <4, that means that angles TKL and TLK, which are each supplementary to either angle 3 or 4, are congruent because, since angles 3 and 4 are congruent, they are congruent because the supplements of congruent angles are congruent.
Answer:
C and D are the right answers
Step-by-step explanation:
Answer:
(1, 2)
Step-by-step explanation:
Given the equation of the lines x + 2y = 5 and 2x - 3y = -4
First we need to make x the subject of the formulas
For x+2y = 5
x = 5 - 2y ... 1
For 2x - 3y = -4
2x = -4+3y
x = (-4+3y)/2 ... 2
Equate 1 and 2
5 - 2y = (-4+3y)/2
2(5-2y) = -4+3y
10 - 4y = -4+3y
-4 -3y = -4-10
-7y = -14
y = 14/7
y = 2
Substitute y = 2 into 1
x = 5 = 2y
x = 5 - 2(2)
x = 5 - 4
x = 1
Hence the point where the lines meet will be at (1, 2)
9514 1404 393
Answer:
5187
Step-by-step explanation:
At the end of 1 hour, the count is 2.5% greater than at the beginning.
5060 + 2.5% × 5060 = 5060 +126.5 = 5186.5
The count at the end of the hour was about 5187.
Step-by-step explanation:
Derive an expression for the equivalent width in a saturated line. Assume a Voigt profile, with the difference in optical depth between the center of the line and the wings being ~104. The wings of the line can be ignored. Define a frequency x1 = (v1 − v0)/ΔvD, where the optical depth τv = 1. Inside of x1 the line is fully saturated, and outside x1 the line is optically thin. Show that the equivalent width is

Note that the equivalent width is practically insensitive to the number density of absorbing material.
