All categories

3 years ago

49/63 reduced fraction

2 answers:

5 0

To reduce a fraction, you must find what number goes into both the numerator and denominator evenly.

In this case, 7 goes into each number evenly.

All we need to do now is divide each number by 7.

$49\div7=7\\63\div7=9\\\\\frac{7}{9}$

marin [14]3 years ago

3 0

49 / 7 = 7
63 / 7 = 9,
You place 7 over 9 and you get your answer!

7/9

You might be interested in

A high school football pennant is in the shape of an isosceles triangle. The base is 18 inches long. The sides meet at an angle

Oksanka [162]

Answer:

The length of each side is 26.3 cm

Step-by-step explanation:

Opposite sides of an isoceles triangle are equal

The isoceles triangle is divided into 2 right-angled triangles so the length of one side can be calculated using trigonometric ratio

When the isoceles triangle is divided, the angle in the right-angled triangle is 20° (1/2 of 40°) and the base is 9cm (1/2 of 18 cm), the hypotenuse side is calculated using trigonometric ratio

Let the length of the hypotenuse side be y

9/y = sin 20°

y = 9/0.3420 = 26.3

Length of each side is 26.3 cm

3 0

3 years ago

You work for a horse farrier. You take a random sample of 75 Quarter Horses and determine that their mean height is 15.2 hands.

Evgesh-ka [11]

Answer:

B) You conclude that the mean height of all Quarter Horses is close to 15.2 hands

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

This was due yesterday please help

Marianna [84]

Answer: 2.1925153x10 to the 3rd

Step-by-step explanation: hope it helps

3 0

2 years ago

Need help again math 7th grade

Olenka [21]

Answer: 1/2 as a fraction

.5 as a decimal

Step-by-step explanation: The probability of them rolling a number would be 3/6 or simplified 1/2 because if there is a 6 sided dice the denominator would be 6 and there are 3 odd numbers on the dice which are 1,3,and 5 so if u have to simplify it would be 1/2 if not 3/6. Also 1/2 as a decimal would be .5

4 0

2 years ago

Read 2 more answers

Find a cubic function with the given zeros.

Fed [463]

Answer:

The correct option is D) $f(x) = x^3 + 2x^2 - 2x - 4$ .

Step-by-step explanation:

Consider the provided cubic function.

We need to find the equation having zeros: Square root of two, negative Square root of two, and -2.

A "zero" of a given function is an input value that produces an output of 0.

Substitute the value of zeros in the provided options to check.

Substitute x=-2 in $f(x) = x^3 + 2x^2 - 2x + 4$ .

$f(x) = x^3 + 2x^2 - 2x + 4\\f(x) = (-2)^3 + 2(-2)^2 - 2(-2) + 4\\f(x) =-8 + 2(4)+4 + 4\\f(x) =8$

Therefore, the option is incorrect.

Substitute x=-2 in $f(x) = x^3 + 2x^2 + 2x - 4$ .

$f(x) = x^3 + 2x^2 + 2x - 4\\f(x) = (-2)^3 + 2(-2)^2 + 2(-2) - 4\\f(x) =-8+2(4)-4-4\\f(x) =-8$

Therefore, the option is incorrect.

Substitute x=-2 in $f(x) = x^3 - 2x^2 - 2x - 4$ .

$f(x) = x^3 - 2x^2 - 2x - 4\\f(x) = (-2)^3 - 2(-2)^2 - 2(-2) - 4\\f(x) =-8-8+4-4\\f(x) =-16$

Therefore, the option is incorrect.

Substitute x=-2 in $f(x) = x^3 + 2x^2 - 2x - 4$ .

$f(x) = x^3 + 2x^2 - 2x - 4\\f(x) = (-2)^3+2(-2)^2 - 2(-2) - 4\\f(x) =-8+8+4-4\\f(x) =0$

Now check for other roots as well.

Substitute x=√2 in $f(x) = x^3 + 2x^2 - 2x - 4$ .

$f(x) = x^3 + 2x^2 - 2x - 4\\f(x) = (\sqrt{2})^3+2(\sqrt{2})^2 - 2(\sqrt{2}) - 4\\f(x) =2\sqrt{2}+4-2\sqrt{2}-4\\f(x) =0$

Substitute x=-√2 in $f(x) = x^3 + 2x^2 - 2x - 4$ .

$f(x) = x^3 + 2x^2 - 2x - 4\\f(x) = (-\sqrt{2})^3+2(-\sqrt{2})^2 - 2(-\sqrt{2}) - 4\\f(x) =-2\sqrt{2}+4+2\sqrt{2}-4\\f(x) =0$

Therefore, the option is correct.

8 0

3 years ago