Is there anything else to the problem
An isosceles triangle has two equal sides.
a= one equal side
b=base
b+2a=35
a=b+4
b+ 2(b+4)=35
b+2b+8=35
3b+8=35
3b=27
b=9
a=13
<h3><u>25</u> ( <u>13</u><u> </u> - <u>3</u><u>)</u></h3><h3> 6 ( 3 2)</h3>
<u>25</u><u> </u><u> </u>( <u>39 -9)</u>
6 (6)
<u>2</u><u>5</u><u> </u> × <u>30</u>
6 6
<u>125</u>
6
20 <u> 5</u><u> </u><u> </u> [ans]
6
Answer:
25
Step-by-step explanation:
Ok so all you have to do is set SPR and QPR equal like this
4x+11=5x-4
and solve to get x=15
then substitute in 15 for x in both equations
4(15)+11 and 5(15)-4
both =71 and add them up to get SPQ=142.
