Hi,
To solve this problem, Let us take the LCM of 10 and 16 which will come 80.
Now suppose the cost price of 10 tables =₹n CP of 80 tables will be ₹ 8n
According to the question, CP of 10 tables is equal to the SP of 16 tables, then
the SP of 16 tables will also be ₹ n.
So, SP of 80 tables will be ₹ 5n
So, Loss = CP-SP
→ 8n - 5n = ₹ 3n
Loss%= (3n×100)/8n
Loss%= 37.5%.
Hence the correct answer will be a <u>loss of 37.5%.</u>
Answer:
-1/53
Step-by-step explanation:
let's firstly convert both fractions with the same denominator, by simply <u>multiplying each fraction by the other's denominator</u>, let's proceed.
![\bf -\cfrac{3}{4}\cdot \cfrac{3}{3}\implies \boxed{-\cfrac{9}{12}}~\hfill -\cfrac{1}{3}\cdot \cfrac{4}{4}\implies \boxed{-\cfrac{4}{12}} \\\\[-0.35em] ~\dotfill\\\\ \boxed{-\cfrac{9}{12}}~~,~~\stackrel{-\frac{2}{3}}{-\cfrac{8}{12}}~~,~~-\cfrac{7}{12}~~,~~\stackrel{-\frac{1}{2}}{-\cfrac{6}{12}}~~,~~-\cfrac{5}{12}~~,~~\boxed{-\cfrac{4}{12}}](https://tex.z-dn.net/?f=%5Cbf%20-%5Ccfrac%7B3%7D%7B4%7D%5Ccdot%20%5Ccfrac%7B3%7D%7B3%7D%5Cimplies%20%5Cboxed%7B-%5Ccfrac%7B9%7D%7B12%7D%7D~%5Chfill%20-%5Ccfrac%7B1%7D%7B3%7D%5Ccdot%20%5Ccfrac%7B4%7D%7B4%7D%5Cimplies%20%5Cboxed%7B-%5Ccfrac%7B4%7D%7B12%7D%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cboxed%7B-%5Ccfrac%7B9%7D%7B12%7D%7D~~%2C~~%5Cstackrel%7B-%5Cfrac%7B2%7D%7B3%7D%7D%7B-%5Ccfrac%7B8%7D%7B12%7D%7D~~%2C~~-%5Ccfrac%7B7%7D%7B12%7D~~%2C~~%5Cstackrel%7B-%5Cfrac%7B1%7D%7B2%7D%7D%7B-%5Ccfrac%7B6%7D%7B12%7D%7D~~%2C~~-%5Ccfrac%7B5%7D%7B12%7D~~%2C~~%5Cboxed%7B-%5Ccfrac%7B4%7D%7B12%7D%7D)
