Answer:
x=8.5
Step-by-step explanation:
∠AOC=68
∠COD= (2x+5)
∠AOC and ∠COD are complimentary angles. This means that when you add them together you get 90.
∠AOC + ∠COD = 90
68 + (2x+5) =90
2x+5=22
2x=17
x=8.5
X^2-22x-48=0
x^2-24x+2x-48=0
x(x-24)+2(x-24)
(x+2)(x-24)
Solve by grouping if you are able to find distinct factors that multiply to the last term and add to the middle term...this method is rather easy with easy to manage numbers. Complete the square if you cannot find distinct factors that multiply to the last term and add to the middle term. Completing the square helps when the equation is in the form of a parabola.
The length and width of a rectangular field fully enclosed with 218 metes fencing are 63 meters and 46 meters respectively.
The perimeter of a rectangle is the sum of the whole four sides. Therefore, the perimeter of a rectangle is defined as follows:
where
l = length
w = width
perimeter = 218 meters
The length of the field is 17 meters longer than the width, w. Therefore, the length is defined as follows:
The length and the width can be calculated as follows:
218 = 2(l + w)
218 = 2(17 + w + w)
218 = 34 + 4w
218 - 34 = 4w
184 = 4w
divide both sides by 4
w = 184 / 4
w = 46 meters
length = 17 + 46
length = 63 meters
learn more on rectangle here: brainly.com/question/15989799?referrer=searchResul
If you mean the one is repeating as 2.1111111....
You would write the decimal as a mixed number of 2 and 1/9 as 1/9 would equal to the 0.1111111.
Hope that helps!
In the study the total number of males was 739 and the total number of all employees was 1501. The men who felt stressed or tensed out during work were 244 and those that never felt stressed out were 495.
Assuming that, A= Employed adults was male and B= Employed adult felt tense or stress out at work.
Then , P(A/B) = P(A∩B)/ P(B)
P(B) is the probability of having a male.
P(B) = 739/1501
P(A∩B) is the probability of a man being stressed or tensed out at work.
and P(A∩B) = 244/ 1501
Hence, P(A/B) =(244/1501)/ (739/1501)
= 244/739
= 0.3302.
Thus, the probability that the employed work felt tense or stress at work given that the employed employee was male is 0.3302
