<h2>Adding Functions</h2><h3>
Answer:</h3>

<h3>
Step-by-step explanation:</h3>
Before we can solve for
, we need to know how
is defined.

We can now solve for
:

Answer: here is your steps Simplifying
8x + -37 = 5x + 17
Reorder the terms:
-37 + 8x = 5x + 17
Reorder the terms:
-37 + 8x = 17 + 5x
Solving
-37 + 8x = 17 + 5x
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '-5x' to each side of the equation.
-37 + 8x + -5x = 17 + 5x + -5x
Combine like terms: 8x + -5x = 3x
-37 + 3x = 17 + 5x + -5x
Combine like terms: 5x + -5x = 0
-37 + 3x = 17 + 0
-37 + 3x = 17
Add '37' to each side of the equation.
-37 + 37 + 3x = 17 + 37
Combine like terms: -37 + 37 = 0
0 + 3x = 17 + 37
3x = 17 + 37
Combine like terms: 17 + 37 = 54
3x = 54
Divide each side by '3'.
x = 18
Simplifying
x = 18
Step-by-step explanation:
Answer:
z = -0.4.
Step-by-step explanation:
Here's the formula for finding the z-score (a.k.a. standardized normal variable) of one measurement
of a normal random variable
:
,
where
is the z-score of this measurement,
is the value of this measurement,
is the mean of the random normal variable, and
is the standard deviation (the square root of variance) of the random normal variable.
Let the length of a trout in this lake be
inches.
.
, and
.
For this measurement,
. Apply the formula to get the z-score:
.
The measure off DF is 11.
In a circle inscribed within a triangle, the distance from each vertex of the triangle to the two nearest touchpoints (points of tangency on the circle) are equal. Since SD=4, DT=4 as well. Since UF=7, then FT=7.
DF=DT+TF=4+7=11.
Answer:
480m³
Step-by-step explanation:
The entire pool have the same depth which is 4metres
Since the pool is L shaped, we will find the volume of each part and add them together to get the volume of the entire pool.
Using the formula for calculating volume of a rectangular box
V = lwh
L is the length
w is the width
h is he height
For the first pool.
Length = 8m
Width = 6m
Height = 4m (depth)
Volume = 8×6×4
Volume = 192m³
For the other pool.
Length = 12m
Width = 6m
Height = 4m (depth)
Volume = 12×6×4
Volume = 288m³
Volume of the entire pool = 192+288 = 480m³