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2 years ago

Determine the x- and y-intercepts for the two lines below and then use them to graph each line.

Mathematics

1 answer:

zavuch27 [327]2 years ago

7 0

Answer:

a. x - 2y = 4

Step-by-step explanation:

carry on learning

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What is the radius of a circle with the equation x2 + y2 – 14x + 10y = 250?

ololo11 [35]

X2 + y2 - 14x + 10y = 250
x2 -14x + 49 - 49 + y2 + 10x + 25 - 25 = 250
(x - 7)^2 - 49 + (y+5)^2 - 25 = 250
(x-7)^2 + (y+5)^2 = 250 + 49 + 25
(x-7)^2 + (y+5)^2 = 324

Therefore the radius, r
r = 324^0.5
r = 18

4 0

3 years ago

(50 Points)

Yanka [14]

C
If you plug in the values in that equation, it works.

5 0

3 years ago

Read 2 more answers

Jerry was using matrices to solve the system of three equations. He has shown all his steps. Did he make a mistake if so in what

melomori [17]

There are several ways to solve a system of equation; one of these ways is the use of matrix.

<em>Jerry made a mistake at step 2</em>

From the attachment, the step 1 is represented as:

$\mathbf{\frac 12R_1 \left[\begin{array}{cccc}1&1&1&0\\5&3&-2&-4\\3&2&1&1\end{array}\right] }$

The equation in step 2 is given as:

$\mathbf{R_2 = 5R_1 - R_2}$

This means that:

We subtract the elements of row 2 from the elements of row 1, multiplied by 5

So, we have:

$\mathbf{R_2 = 5\left[\begin{array}{cccc}1&1&1&0\end{array}\right] } - \left[\begin{array}{cccc}5&3&-2&-4\end{array}\right] }$

Expand

$\mathbf{R_2 = \left[\begin{array}{cccc}5&5&5&0\end{array}\right] } - \left[\begin{array}{cccc}5&3&-2&-4\end{array}\right] }$

Subtract corresponding cells

$\mathbf{R_2 = \left[\begin{array}{cccc}0&2&7&4\end{array}\right] }$

So, the new row 2 elements should be:

$\mathbf{ \left[\begin{array}{cccc}0&2&7&4\end{array}\right] }$

However, the row 2 elements of Jerry's steps are:

$\mathbf{R_2 = \left[\begin{array}{cccc}0&-2&-7&-4\end{array}\right] }$

This means that:

Jerry made a mistake; and the mistake is at step 2