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3 years ago

Witch is NOT a method for solving systems of a linear equations

Mathematics

1 answer:

vekshin13 years ago

5 0

Answer:

b. fundamental arithmetic

Step-by-step explanation:

While fundamental arithmetic is required when solving linear equations, the use of it is not a named <em>method of solution</em>.

"Substitution", "Elimination", and "Graphing" are named methods of solving linear equations. Sometimes the line can be blurred between substitution and elimination, but these methods generally involve distinct sets of steps (which include the use of fundamental arithmetic).

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Ab^2-4/10 when a=4 b=6

hammer [34]

$\huge\text{Hey there!}$

$\large\boxed{\rm{\dfrac{ab^2 - 4}{10}}}$

$\large\boxed{\rm{\rightarrow\dfrac{\bold{4(6)}^2 -4}{10}}}$

$\large\boxed{\rm{6^2}}$

$\large\boxed{\rm{= 6 \times6}}$

$\large\boxed{\rm{= \bf 36}}$

$\large\boxed{\rm{\rightarrow\dfrac{4(\bold{36)}- 4}{10}}}}$

$\large\boxed{\rm{4(36)}}$

$\large\boxed{\rm{= \bf 144}}}$

$\large\boxed{\rm{\rightarrow\dfrac{\bold{144} - 4}{10}}}$

$\large\boxed{\rm{\bold{144} - 4}}$

$\large\boxed{= \rm{\bf 140}}}$

$\large\boxed{\rm{\rightarrow\dfrac{\bold{140}}{10}}}$

$\large\boxed{\rm{= \bf 14}}$

$\huge\boxed{\rm{Therefore, your\ answer\ is: \mathsf{14}}}\huge\checkmark$

$\huge\text{Good luck on your assignment \& enjoy your day!}$

~ $\frak{Amphitrite1040:)}$

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Eduardwww [97]

Answer:

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Step-by-step explanation:

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