All categories

3 years ago

The standard deviation and the mean of 16 values are 15.6 and 20.5. What is the coefficient of variation ?

Mathematics

1 answer:

EastWind [94]3 years ago

5 0

Answer:

CV = coefficient of variation = 0.761

Step-by-step explanation:

The coefficient of variation is defined as the standard deviation divided by the mean of a population, which in this case,

standard deviation = 15.6

mean = 20.5

CV = coefficient of variation = 15.6/20.5 = 0.761

Note that if the 16 values form a sample (i.e. not the entire population), the above result is an estimate of the CV.

You might be interested in

A boy named Tyler is paid $25 a day plus $0.25 cents for every newspaper he delivered. After his first day of work, he was paid

DerKrebs [107]

Step-by-step explanation:

equation:

25 + .25x = 225

solution:

.25x = 200

x = 800 newspapers

8 0

3 years ago

Using Cramer's Rule, what are the values of x and y in the solutio

olya-2409 [2.1K]

Answer:

x = -3, y = 1

Step-by-step explanation:

To find the value of x and y, find the determinant of original matrix, which would be 21.

Then, substitute the value of x with the solutions to the equations and find the determinant of that matrix, which is -63.

Cramer's rule says that Dx ÷ D is the value of x. So, -63 ÷ 21 = -3.

So, the x-value is -3.

You can find the determinant of the y-value in the same way, and you'll find out that y = 1.

Hope this helped! :)

8 0

3 years ago

What is the period of the function f(x)=sin(x/2)

Liula [17]

The period of the function is 2pi

3 0

3 years ago

Which graph represents a function with an initial value of One-half?

sweet [91]

Answer:

The answer is B

Step-by-step explanation:

I went on socratic and found the answer

7 0

3 years ago

Find the exact values of a) sec of theta b)tan of theta if cos of theta= -4/5 and sin<0

Gre4nikov [31]

Answer:

Using trigonometric ratio:

$\sec \theta = \frac{1}{\cos \theta}$

$\tan \theta = \frac{\sin \theta}{\cos \theta}$

From the given statement:

$\cos \theta = -\frac{4}{5}$ and sin < 0

⇒ $\theta$ lies in the 3rd quadrant.

then;

$\sec \theta = \frac{1}{-\frac{4}{5}} = -\frac{5}{4}$

Using trigonometry identities:

$\sin \theta = \pm \sqrt{1-\cos^2 \theta}$

Substitute the given values we have;

$\sin \theta = \pm\sqrt{1-(\frac{-4}{5})^2 } =\pm\sqrt{1-\frac{16}{25}} =\pm\sqrt{\frac{25-16}{25}} =\pm \sqrt{\frac{9}{25} } = \pm\frac{3}{5}$

Since, sin < 0

⇒ $\sin \theta = -\frac{3}{5}$

now, find $\tan \theta$ :

$\tan \theta = \frac{\sin \theta}{\cos \theta}$

Substitute the given values we have;

$\tan \theta = \frac{-\frac{3}{5} }{-\frac{4}{5} } = \frac{3}{5}\times \frac{5}{4} = \frac{3}{4}$

Therefore, the exact value of:

(a)

$\sec \theta =-\frac{5}{4}$

(b)

$\tan \theta= \frac{3}{4}$

7 0

3 years ago

The standard deviation and the mean of 16 values are 15.6 and 20.5. What is the coefficient of variation ?​

The standard deviation and the mean of 16 values are 15.6 and 20.5. What is the coefficient of variation ?