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3 years ago

A football team loses 5 yards on each of 3 consecutive plays.

Mathematics

1 answer:

nalin [4]3 years ago

6 0

My answer will be -5*3=-15

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Jamie scored an 85% on a test that had 20 questions on it. How many question did she get right? How many questions did she get w

SSSSS [86.1K]

Answer:10 wrong

Step-by-step explanation:

I am smart

Hope it helps :)

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3 years ago

2<br> the function f(x)=-x+4x-3

Hunter-Best [27]

The function of f(x)=-x+4x-3 is 3x-3. I hope this helps. :)

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3 years ago

Dean sot a goal to do more than 900 push-ups this month. So far, he has done 230 push-ups, and there are 20 more days remaining

vampirchik [111]

Step-by-step explanation:

he has 900-230 = 670 more push-ups to do in the remaining 20 days.

so, he has to do every day

670/20 = 67/2 = 33.5 push-ups.

fractions of push-ups don't make sense.

we cannot say, he has to do at least 33 per day, because then he might come short in the end (if he sticks to the low limit) .

so, we have to say he has to do more than 33 or at least 34 push-ups per day to be sure he will at least reach his goal.

p > 33

p >= 34

both should be correct in the context of using only whole numbers.

bur in case of doubt I would pick p >= 34.

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2 years ago

A small combination lock on a suitcase has 55 wheels, each labeled with the 10 digits 0 to 9. How many 55 digit combinations ar

den301095 [7]

Suppose $a_n$ is the number of possible combinations for a suitcase with a lock consisting of $n$ wheels. If you added one more wheel onto the lock, there would only be 9 allowed possible digits you can use for the new wheel. This means the number of possible combinations for $n+1$ wheels, or $a_{n+1}$ is given recursively by the formula

$a_{n+1}=9a_n$

starting with $a_1=10$ (because you can start the combination with any one of the ten available digits 0 through 9).

For example, if the combination for a 3-wheel lock is 282, then a 4-wheel lock can be any one of 2820, 2821, 2823, ..., 2829 (nine possibilities depending on the second-to-last digit).

By substitution, you have

$a_{n+1}=9a_n=9^2a_{n-1}=9^3a_{n-2}=\cdots=9^na_1=10\times9^n$

This means a lock with 55 wheels will have

$a_{55}=10\times9^{54}$

possible combinations (a number with 53 digits).

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3 years ago

what is the formula for to find the surface area of a triangular prism and which one is the height and which one is the zbase

Nina [5.8K]

A= (a+b+c)h is the formula. I hope this is helpful for you. I am pretty positive it will help.

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3 years ago