The graph you chose has a y intercept of 5. In other words, the point (0,5) is on that graph. However, if we plugged x = 0 into the function f(x), we get
f(x) = 3*5^x
f(0) = 3*5^0
f(0) = 3*1
f(0) = 3
So the point (0,3) is actually on the graph. The graph is increasing. So the answer is the upper left corner (instead of the upper right corner)
The values of x that will give the quadratic equation no real number solutions are -5 and 9
<h3>What are real roots of a quadratic equation?</h3>
Real roots of a quadratic equation are values of x, whose numbers can be represented on a number line.
Analysis:
We have -
+3x +c = 0
- 4ac is called the discriminant of a quadratic equation.
if - 4ac < 0, then the quadratic equation has no real root.
where a = -1, b = 3 c = c
-4(-1)c < 0
9 + 4c < 0
4c < -9
c < -9/2
Which means values lower than -9/2 would give the solution no real root.
From, the options, only -5 would give no real solution, since it is lower than -9/2.
Learn more about real roots of a quadratic equation: brainly.com/question/7784687
#SPJ1
The answer to this question is 110.3 ft. Hope this helps.
<em>Hey</em><em>!</em><em>!</em>
<em>Sol</em><em>ution</em><em>,</em>
<em>(</em><em>5</em><em>)</em><em>^</em><em>-</em><em>2</em>
<em>=</em><em>1</em><em>/</em><em>5</em><em>^</em><em>2</em>
<em>=</em><em>1</em><em>/</em><em>2</em><em>5</em>
<em>The</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>1</em><em>/</em><em>2</em><em>5</em>
<em>hope</em><em> </em><em>it</em><em> </em><em>helps</em>
<em>Good</em><em> </em><em>luck</em><em> on</em><em> your</em><em> assignment</em>
Answer:
∠ JFK = 57°
Step-by-step explanation:
∠ JFK and ∠ GFH are vertically opposite and congruent , then
∠ JFK = ∠ GFH = 57°
