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jasenka [17]
3 years ago
12

PLEASE DO THIS AND I WILL GIVE YOU BRAINLIEST AND ALOT OF POINTS ALSO DONT JUST DO THIS FOR THE POINTS OR YOU WILL BE REPOTED AN

D ALL ADMINS ARE ONLINE THANK YOU!

Mathematics
1 answer:
ANTONII [103]3 years ago
8 0

16. no i dont agree. 1 is the only number that can multiply and equal itself. also, 0.1 is not even a whole number

17. it took 19 to 21 hours. one way to show work is by long division. i dont know how to do another way im so sorry

18. because 15000 is the amount in 50 minutes, so just divide 50 minutes of phones by 50 to get one minute of phones

i am worn out i cant do the last one

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Company A had a loss of $255 in January. Company B had a profit of $162 in January. What was the difference between the profits
Julli [10]

Answer:

The difference of the profit of two companies is $ 417

Step-by-step explanation:

Given as :

The company A loss amount in January = $ 255

The company B profit amount in January = $ 162

Let the difference between there profits = x

So, x = company B profit - ( company A profit)

I.e x = company B profit - ( - company A loss)

Or, x = $ 255 + $162

∴   x = $ 417

Hence The difference of the profit of two companies is $ 417  . Answer

6 0
3 years ago
A coin is tossed four times What is the probability of getting four heads? (1 mark) a) b) What is the probability of getting exa
BlackZzzverrR [31]
<h2>Answer:</h2>

1. A coin is tossed four times. What is the probability of getting four heads?

Each toss has a 1/2 chance of getting a head.

So the chance of getting all four heads can be calculated as :

1/2\times1/2\times1/2\times1/2=1/16

2. A coin is tossed four times. What is the probability of getting two heads?

Each toss can have 2 results, so 4 flips will have 2^{4} or 16 results.

Getting two heads means getting two tails also. So, we can get the number of times two heads come = \frac{4!}{2!2!} = 6

We can write the groups like - {HHTT,HTHT,HTTH,THHT,THTH,TTHH}

So, the required probability is : 6/16 or 3/8.

3. Not getting two heads means getting 3 tails and 1 head or all tails.

Probability of having all tails = 1/2\times1/2\times1/2\times1/2=1/16

Probability of one head(1st trial) and three tails = 1/16

Probability of one head (2nd trial) and three tails (the 1st, 3rd and 4th trials) = 1/16

Probability of one head (3rd trial) and three tails (the 1st, 2nd and 4th trials) = 1/16

Probability of one head (4th trial) and three tails (the 1st, 2nd and 3rd trials) = 1/16

So, the total probability showing only one or none head and at least three tails = 1/16+1/16+1/16+1/16+1/16=5/16

6 0
3 years ago
Please help me! What is the simplest form for 21 /63 ?
creativ13 [48]

Answer:

1/3

Step-by-step explanation:


5 0
4 years ago
A company rents water tanks shaped like cylinders. Each tank has a radius of 3 feet and a height of 2 feet. The cost is $4 per c
vivado [14]

Answer:

Cost to rent one tank=226.08 Dollars

Step-by-step explanation:

Radius of the cylindrical tank=3 feet

Height of the tank= 2 feet

Cost to rent one tank= Volume of one tank * cost to rent one cubic feet of volume

Volume of the cylindrical tank:

                                         =\pi r^2

As,  \pi =\frac{22}{7}=3.14

Putting the values in the formula:

Volume of the tank:

                                    =3.14*(3*3)*2\\\\=3.14*9*2\\\\=3.14*18\\\\=56.52feet^3

Cost to rent one cubic feet= 4 Dollars

Cost to rent 56.52 Cubic feet of one tank;

   = 4*56.52

=226.08 Dollars

5 0
3 years ago
LONG WORD PROBLEM I KNOW! PLEASE ILL GIVE THANKS BRAINLIEST AND POINTS FOR THIS ANSWER! PLEASE!
11Alexandr11 [23.1K]
Answer:
5X + 8Y >= 300; intersection at (-20, 50)
Step-by-step explanation:
let t = work hours
0 < t < 30
X = time lawn mowing
Y = time babysitting.
X + Y < 30
5X + 8Y >= 300
We could solve...
X < 30 - Y
5(30 - Y) + 8Y >=300
150 - 5Y + 8Y >= 300
3Y >=150
Y >=50
then X < -20
intersection at (-20, 50)
5 0
3 years ago
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