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2 years ago

14

The afternoon temperature in biscoff bay was -2 Fahrenheit by midnight a warm front move in and the temperature goes to 11 Fahre

nheit what was the change in the temperature from afternoon to MidnightA. 7B. 3C. 6D. 13

1 answer:

timofeeve [1]2 years ago

6 0

Answer:

D. 13

Step-by-step explanation:

You find the difference of the two temperatures

11-(-2)

11+2

13

You might be interested in

The operation manager at a tire manufacturing company believes that the mean mileage of a tire is 30,393 miles, with a standard

Pie

Answer:

52.84% probability that the sample mean would differ from the population mean by less than 339 miles in a sample of 37 tires if the manager is correct

Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the central limit theorem:

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$

In this problem, we have that:

$\mu = 30393, \sigma = 2876, n = 37, s = \frac{2876}{\sqrt{37}} = 472.81$

What is the probability that the sample mean would differ from the population mean by less than 339 miles in a sample of 37 tires if the manager is correct

This probability is the pvalue of Z when X = 30393 + 339 = 30732 subtracted by the pvalue of Z when X = 30393 - 339 = 30054. So

X = 30732

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{30732 - 30393}{472.81}$

$Z = 0.72$

$Z = 0.72$ has a pvalue of 0.7642.

X = 30054

$Z = \frac{X - \mu}{s}$

$Z = \frac{30054 - 30393}{472.81}$

$Z = -0.72$

$Z = -0.72$ has a pvalue of 0.2358

0.7642 - 0.2358 = 0.5284

52.84% probability that the sample mean would differ from the population mean by less than 339 miles in a sample of 37 tires if the manager is correct

4 0

3 years ago

I need help with this someone very smart at math this algebra 2

Mrac [35]

Answer:

value if a =

$\frac{5}{4}$

Step-by-step explanation:

here's the solution :-

=》

$\frac{ 2(\sqrt{m}) {}^{3} }{ \sqrt[4]{m} }$

=》

$\frac{2(m {}^{ \frac{1}{2}} ) {}^{3} }{ {m}^{ \frac{1}{4} } }$

=》

$\frac{2 {m}^{ \frac{3}{2} }} { {m}^{ \frac{1}{4} } }$

=》

$2m {}^{ \frac{3}{2} - \frac{1}{4} }$

=》

$2m {}^{ \frac{6 - 1}{4} }$

=》

$2m {}^{ \frac{5}{4} }$

so, a = 5/4

6 0

2 years ago

Could someone pls help me out? Thank u so much

vesna_86 [32]

Answer:

$25

Step-by-step explanation:

c=30−(0.25)(20)

c=30+(−5)

c=(30+(−5)

30-5

Combine Like Terms

c=25

8 0

2 years ago

ASAP!!! Pls help me out :(

mr_godi [17]

The answer you are looking for is B. 70.69

3 0

3 years ago

Read 2 more answers

HELP!!!!!!!!!!!!!!!!!!!!! Do all real numbers have a decimal expansion? Select each correct answer. Some numbers, such as 1 10

ankoles [38]

Answer:

1. Some numbers, such as $\frac{1}{10}$ , have a decimal expansion that terminates.

2. All real numbers have a decimal expansion.

5. Some numbers, such as $\frac{1}{18}$ , have a decimal expansion that repeats but does not terminate.

Step-by-step explanation:

According to the options, we have,

1. Some numbers, such as $\frac{1}{10}$ , have a decimal expansion that terminates.

It is correct as the decimal expansion of $\frac{1}{10}$ is 0.1, which terminates.

2. All real numbers have a decimal expansion.

This is also correct as both rational and irrational numbers can be written in decimal form.

3. Some numbers, such as $\sqrt{13}$ do not have a decimal expansion

This is not correct as $\sqrt{13}=3.605551275$ i.e. it has a decimal expansion.

4. Only some real numbers have a decimal expansion.

It is not correct as 2 is correct.

5. Some numbers, such as $\frac{1}{18}$ , have a decimal expansion that repeats but does not terminate.

It is correct as $\frac{1}{18}=0.0555555..$ , which is non-terminating decimal expansion.

So, the correct options are,

1. Some numbers, such as $\frac{1}{10}$ , have a decimal expansion that terminates.

2. All real numbers have a decimal expansion.

5. Some numbers, such as $\frac{1}{18}$ , have a decimal expansion that repeats but does not terminate.

6 0

3 years ago