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givi [52]
2 years ago
14

The afternoon temperature in biscoff bay was -2 Fahrenheit by midnight a warm front move in and the temperature goes to 11 Fahre

nheit what was the change in the temperature from afternoon to MidnightA. 7B. 3C. 6D. 13
Mathematics
1 answer:
timofeeve [1]2 years ago
6 0

Answer:

D. 13

Step-by-step explanation:

You find the difference of the two temperatures

11-(-2)

11+2

13

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Compute a · (b ✕ c), where a = i − 3j + k, b = 4i + j + k and c = 9i − j + 3k.
grandymaker [24]
\mathbf a=\mathbf i-3\,\mathbf j+\mathbf k
\mathbf b=4\,\mathbf i+\mathbf j+\mathbf k
\mathbf c=9\,\mathbf i-\mathbf j+3\,\mathbf k

\mathbf b\times\mathbf c=\begin{vmatrix}\mathbf i&\mathbf j&\mathbf k\\4&1&1\\9&-1&3\end{vmatrix}=4\,\mathbf i-3\,\mathbf j-13\,\mathbf k

\mathbf a\cdot(\mathbf b\times\mathbf c)=(\mathbf i-3\,\mathbf j+\mathbf k)\cdot(2\,\mathbf i-3\,\mathbf j-13\,\mathbf k)=4+(-3)^2-13=0
6 0
3 years ago
Solve the word problem below. Enter your answer as a fraction in simplest
belka [17]

Answer:

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Step-by-step explanation:

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3 0
3 years ago
Pls help with this question
Talja [164]

Answer:

point A is x=4 and y=12

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6 0
2 years ago
Which of the following values are zeros for the function below g(x)=(x2+4x-12)(x-3)
Brilliant_brown [7]

Answer:

<h2>-6, 2 and 3</h2>

Step-by-step explanation:

g(x)=(x^2+4x-12)(x-3)=(x^2+6x-2x-12)(x-3)\\\\=[x(x+6)-2(x+6)](x-3)=(x+6)(x-2)(x-3)\\\\\text{The zeros for}\ g(x)=0:\\\\(x+6)(x-2)(x-3)=0\iff x+6=0\ \vee\ x-2=0\ \vee\ x-3=0\\\\x=-6\ \vee\ x=2\ \vee\ x=3

4 0
3 years ago
I need help finding the missing angles, please show work
Leno4ka [110]
It's an isosceles triangle, which means base angles are equal.

48 = 6x

48/6 = x

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Angle y = 84°

The two missing angles are 48° and 84°.
7 0
3 years ago
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