Answer:
Step-by-step explanation:
“the center of the ellipse is located below the given co-vertex”
Co-vertex and center are vertically aligned, so the ellipse is horizontal.
Equation for horizontal ellipse:
(x-h)²/a² + (y-k)²/b² = 1
with
a² ≥ b²
center (h,k)
vertices (h±a, k)
co-vertices (h, k±b)
foci (h±c,k), c² = a² -b²
One co-vertex is (-8,9), so h = -8.
One focus is (4,4), so k = 4.
Center (h,k) = (-8,4)
c = distance between center and focus = |-8 - 4| = 12
b = |9-k| = 5
a² = c² + b² = 169
(x+8)²/169 + (y-4)²/25 = 1
Answer: 50
Step-by-step explanation: 42x12=504. 504-4=500. 500/10=50.
You're performing this kind of transformation:

This kind of transformations translate the functions vertically k units up if k is positive, k units down if k is negative.
So, in your case, you translate the function 7 units down.
Answer:
Perimeter of i - 22CM
Area of i - 13CM^2
Perimeter of ii -38CM
Area of ii -66CM^2
Perimeter of iii -30CM
Area of iii- 42CM^2
Perimeter of iv - 50CM
Area of iv- 126CM^2
Step-by-step explanation:
SHAPE I:
PERIMETER = S + S + S + S + S +S
= 7 + 1 + 5 +3 +4 +2
= 22CM
AREA = Part a - 4 * 2 = 8cm^2 part B - 5 *1 = 5cm^2
Total = 8 + 5 = 13cm^2
SHAPE II:
PERIMETER = S + S + S + S + S +S
= 4 + 4 +5 + 6 + 9 + 10
= 38 CM
AREA = Part a - 5 * 10 = 50 cm^2 part B - 4 *4 =16 cm^2
Total = 50+16 =66 cm^2
SHAPE III:
PERIMETER = S + S + S + S + S +S
= 9 + 2 + 3 + 4 + 6 + 6
= 30CM
AREA = Part a - 6 * 6 = 42cm^2 part B - 3 * 2= 6cm^2
Total = 36 + 6 =42 cm^2
SHAPE IV:
PERIMETER = S + S + S + S + S +S
= 9 + 10 + 4 + 6 + 6 + 15
= 50 CM
AREA = Part a -15 * 6 = 90 cm^2 part B - 9 *4 = 36cm^2
Total = 90 + 36 = 126cm^2
HOPE THIS HELPED
Answer:
that is a pretty lightly detailed question but the safest numbers to go by would be 2 and 3
Step-by-step explanation: