Answer:
See explaination
Explanation:
The code
type printer = monitor
var P: array[0…2] of boolean;
X: condition;
procedure acquire (id: integer, printer-id: integer);
begin
if P[0] and P[1] and P[2] then X.wait(id)
if not P[0] then printer-id := 0;
else if not P[1] then printer-id := 1;
else printer-id := 2;
P[printer-id]:=true;
end;
procedure release (printer-id: integer)
begin
P[printer-id]:=false;
X.signal;
end;
begin
P[0] := P[1] := P[2] := false;
end ;
Note:
Monitors are implemented by using queues to keep track of the processes attempting to become active int he monitor. To be active, a monitor must obtain a lock to allow it to execute the monitor code. Processes that are blocked are put in a queue of processes waiting for an unblocking event to occur.
I believe you go to the the tools selection or just click control alt space
Answer:
/*
* Program to write data to text file.
*/
#include<iostream>
#include<fstream>
#include<string.h>
using namespace std;
int main()
{
//Variable to name and age of a person.
string name;
int age;
cout<<"Enter your name"<<endl;
cin>>name;
cout<<"Enter your age"<<endl;
cin>>age;
//Creating object of ofstream.
ofstream file;
file.open ("outdata.txt");
//Writing data to file named outdata.txt
file<<name<<" "<<age;
file.close();
}
Output:
Enter your name
John
Enter your age
25
Content of Output.txt:
John 25
Explanation:
To write data to a file ofstream object is used. An ofstream object file is created first and then using this object a file named "outdata.txt" is created.
Finally using shift operator (<<), by means of operator overloading, name and age of person is transferred to file outdata.txt.
Answer:
which type of questions is this
Answer:
expr.at(g) returns a string, not a char. They are not the same thing and that is what the compiler is complaining about.
