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Andrew [12]
3 years ago
9

A ________ is a self-contained program that spreads through a computer network by exploiting security holes in the computers con

nected to the network. (Hint: one word)
Computers and Technology
1 answer:
Darya [45]3 years ago
5 0

Answer:

Worm

Explanation:

This is what a worm does! It exploits small security holes in networks and computers.

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The Sleeping-Barber Problem:
s2008m [1.1K]

Answer:

Explanation:

Following are the Semaphores:

Customers: Counts waiting customers;

Barbers: Number of idle barbers (0 or 1)

mutex: Used for mutual exclusion.

Cutting: Ensures that the barber won’t cut another customer’s hair before the previous customer leaves

Shared data variable:

count_cust: Counts waiting customers. ------------copy of customers. As value of semaphores can’t access directly.

// shared data

semaphore customers = 0; semaphore barbers = 0; semaphore cutting = 0; semaphore mutex = 1;

int count_cust= 0;

void barber() {

while(true) { //shop is always open

wait(customers); //sleep when there are no waiting customers

wait(mutex); //mutex for accessing customers1

count_cust= count_cust-1; //customer left

signal(barbers);

signal(mutex);

cut_hair();

}

}

void customer() {

wait(mutex); //mutex for accessing count_cust

if (count_cust< n) {

count_cust= count_cust+1; //new customer

signal(customers); signal(mutex);

wait(barbers); //wait for available barbers get_haircut();

}

else { //do nothing (leave) when all chairs are used. signal(mutex);

}

}

cut_hair(){ waiting(cutting);

}

get_haircut(){

get hair cut for some time; signal(cutting);

}

6 0
3 years ago
g Suppose we want to compress a text consisting of 6 characters,a, b, c, d, e, fusingthe Huffman Algorithm. Give an example for
Papessa [141]

Answer:

e(a) = 0

e(b) = 10

e(c) = 110

e(d) = 1110

Explanation:

The Worst case will happen when f(a) > 2*f(b) ; f(b) > 2*f(c) ; f(c) > 2*f(d) ; f(d) > 2*f(e) and f(e) > 2*f(f).

Where f(x) is frequency of character x.

Lets consider the scenario when

f(a) = 0.555, f(b) = 0.25, f(c) = 0.12, f(d) = 0.05, f(e) = 0.02 and f(f) = 0.005

Please see attachment for image showing the steps of construction of Huffman tree:- see attachment

From the Huffman tree created, we can see that endcoding e() of each character are as follows:-

e(a) = 0

e(b) = 10

e(c) = 110

e(d) = 1110

e(e) = 11110

e(f) = 11111

So we can see that maximum length of encoding is 5 in this case.

3 0
3 years ago
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