Question

What is the equation of the following Graph?

Answer 1

Answer:

From the shape of the graph we can state it is the transformation of the square root function:

• f(x) = $\sqrt{x}$

This is a reflection of f(x) over x-axis, translation 3 units left and 2 units up.

The transformation is:

• g(x) = - f(x + 3) + 2

The equation is:

• g(x) = - $\sqrt{x+3} +2$

Answer 2

You want to find the equation for a line that passes through the two points:

(1,0) and (,).

First of all, remember what the equation of a line is:

y = mx+b

Where:

m is the slope, and

b is the y-intercept

First, let's find what m is, the slope of the line...

The slope of a line is a measure of how fast the line "goes up" or "goes down". A large slope means the line goes up or down really fast (a very steep line). Small slopes means the line isn't very steep. A slope of zero means the line has no steepness at all; it is perfectly horizontal.

For lines like these, the slope is always defined as "the change in y over the change in x" or, in equation form:

So what we need now are the two points you gave that the line passes through. Let's call the first point you gave, (1,0), point #1, so the x and y numbers given will be called x1 and y1. Or, x1=1 and y1=0.

Also, let's call the second point you gave, (,), point #2, so the x and y numbers here will be called x2 and y2. Or, x2= and y2=.

Now, just plug the numbers into the formula for m above, like this:

m=  

- 0

- 1

or...

m=  

0

-1

or...

m=0

So, we have the first piece to finding the equation of this line, and we can fill it into y=mx+b like this:

y=0x+b

Now, what about b, the y-intercept?

To find b, think about what your (x,y) points mean:

(1,0). When x of the line is 1, y of the line must be 0.

(,). When x of the line is , y of the line must be .

Because you said the line passes through each one of these two points, right?

Now, look at our line's equation so far: y=0x+b. b is what we want, the 0 is already set and x and y are just two "free variables" sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the two points (1,0) and (,).

So, why not plug in for x and y from one of our (x,y) points that we know the line passes through? This will allow us to solve for b for the particular line that passes through the two points you gave!.

You can use either (x,y) point you want..the answer will be the same:

(1,0). y=mx+b or 0=0 × 1+b, or solving for b: b=0-(0)(1). b=0.

(,). y=mx+b or =0 × +b, or solving for b: b=-(0)(). b=0.

See! In both cases we got the same value for b. And this completes our problem.

The equation of the line that passes through the points

(1,0) and (,)

is

y=0

Notes:

m came out to be zero, so there is no "mx" term.

b came out to be zero, so there is no "+b" term.