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soldier1979 [14.2K]
2 years ago
11

The Hickory Stick has a selection of 3 meats and 6 vegetables. How many different selections of one meat and one vegetable are p

ossible
Mathematics
1 answer:
valentina_108 [34]2 years ago
7 0

The <u>different</u> selections of<u> one</u> meat and <u>one</u> vegetable are possible are 18 selections.

Since the Hickory Stick has a selection of 3 meats and 6 vegetables, the number of ways we can select <u>one </u>meat out of 3 is ³C₁ = 3.

Also, the number of ways we can select <u>one </u>vegetable out of 6 is ⁶C₁ = 6.

So, the total number of selections of <u>one</u> meat and <u>one</u> vegetable is ³C₁ × ⁶C₁ = 3 × 6

= 18 selections

So, the <u>different</u> selections of<u> one</u> meat and <u>one</u> vegetable are possible are 18 selections.

Learn more about combination here:

brainly.com/question/19341024

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<span>We suggest, that x is the value that we are looking for. </span>
<span>3. If 32 is 100%, so we can jot it down as 32=100%. </span>
<span>4. We know for sure, that x is 15% of the output value, so we can jot it down as x=15%. </span>
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7. Answer for what is 15% of 32

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<span>(32/x)*x=(100/15)*x       - </span>multiply both sides of the equation by x
<span>32=6.66666666667*x       - </span>divide both sides of the equation by (6.66666666667) to get x
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