The answer is 290 but I solved this by mean
6)
KM bisects on <NKL so m<MKN = m<MKL = 3x + 5
2(m<MKL) + m<JKN = 180
2(3x+5) + 8x + 2 = 180
6x + 10 + 8x + 2 = 180
14x + 12 = 180
14x = 168
x = 12
so
m<MKN = m<MKL = 3x + 5 = 3(12) + 5 = 36 + 5 = 41
answer
b. 41
7)
2 supplementary has sum = 180
x + x + 14 = 180
2x + 14 = 180
2x = 166
x = 83
x + 14 = 83 + 14 = 97
2 angles are 83 and 97
answer
b. 83, 97
First seat: 14 candidates to seat
Second seat: 13 candidates to seat
Third seat : 12 candidates
4th seat: 11 candidates
5th seat: 10 candidates
6th seat: 9 candidates
Number of different variations: 14*13*12*11*10*9 = 2,162,160 different ways,
Observe that is 14P6 = 14! / (14-6)! = 14! / 8! = 14*13*12*11*10*9*8! / 8! =
= 14*13*12*11*10*9
Answer: 2,162,160
Answer:
4x + 1 and 6x - 2x - 2 + 3
Step-by-step explanation:
we can expand and find 2 equations that are the same as this
one being 6x+3 -2x -2
and another being 4x + 1
hope this helps!
