Answer:
The answer is B :))
Step-by-step explanation:
Brainliest?
Answer:
proof below
Step-by-step explanation:
Remember that a number is even if it is expressed so n = 2k. It is odd if it is in the form 2k + 1 (k is just an integer)
Let's say we have to odd numbers, 2a + 1, and 2b + 1. We are after the sum of their squares, so we have (2a + 1)^2 + (2b + 1)^2. Now let's expand this;
(2a + 1)^2 + (2b + 1)^2 = 4a^2 + 4a + 4b + 4b^2 + 4b + 2
= 2(2a^2 + 2a + 2b^2 + 2b + 1)
Now the sum in the parenthesis, 2a^2 + 2a + 2b^2 + 2b + 1, is just another integer, which we can pose as k. Remember that 2 times any random integer, either odd or even, is always even. Therefore the sum of the squares of any two odd numbers is always even.
The rule seems to be to add 8. 10+8=18+8=26+8=34+8=42. I hope this helps!
Think: "Find <span>tan-1(0.577)" means "Find the ANGLE in Quadrant III whose tangent is 0.577. Because the angle is in QIII, both the opp side and the adj side are negative. Here you have four answer choices. The correct answer MUST be within the interval 180 and 270 degrees. Only one of the given answer choices satisfies that criterion. Which one is it?
</span><span>tan-1(0.577) = ?</span>
See picture for solution steps and answer.
