Answer:
(5, -2)
Step-by-step explanation:
In the coordinates (7, -5), 7 is the x-coordinate and -5 is the y-coordinate.
The transformation, (x-2 y+3), states that the x-coordinate, 7, must be subtracted by 2.
When subtracted by two, (7 - 2), the difference is 5.
The transformation, (x-2 y+3), states that the y-coordinate must be increased by 3.
When added by 3, (-5 + 3), the sum is -2.
Therefore, the new coordinates are (5, -2).
Answer:
p= 2.5
q= 7
Step-by-step explanation:
The lines should overlap to have infinite solutions, slopes should be same and y-intercepts should be same.
Equations in slope- intercept form:
6x-(2p-3)y-2q-3=0 ⇒ (2p-3)y= 6x -2q-3 ⇒ y= 6/(2p-3)x -(2q+3)/(2p-3)
12x-( 2p-1)y-5q+1=0 ⇒ (2p-1)y= 12x - 5q+1 ⇒ y=12/(2p-1)x - (5q-1)/(2p-1)
Slopes equal:
6/(2p-3)= 12/(2p-1)
6(2p-1)= 12(2p-3)
12p- 6= 24p - 36
12p= 30
p= 30/12
p= 2.5
y-intercepts equal:
(2q+3)/(2p-3)= (5q-1)/(2p-1)
(2q+3)/(2*2.5-3)= (5q-1)/(2*2.5-1)
(2q+3)/2= (5q-1)/4
4(2q+3)= 2(5q-1)
8q+12= 10q- 2
2q= 14
q= 7
Answer:
x > -1
Step-by-step explanation:
Isolate the variable, x. Treat the > sign like an equal sign, what you do to one side, you do to the other.
Subtract 5 from both sides:
x + 5 (-5) > 4 (-5)
x > 4 - 5
x > -1
x > -1 is your answer.
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Answer:
The interquartile range is <em>50.</em>
Step-by-step explanation:
To find our answer we have to first <em>quartile 1</em> and <em>quartile 3</em> are equal too. When we look at the plot <em>quartile 1 </em>is equal to <em>20,</em> <em>quartile 3 </em>is equal to <em>70</em> because it is in between <em>60</em> and <em>80</em>. Now to find the interquartile range we will <em>subtract 70</em> from <em>20</em> and we get <em>50</em>. Therefore, <u><em>50</em></u><em> is our answer.</em>
Answer:
1556963
Step-by-step explanation:
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