20 - 4 TIMES 4 DIVIDE 2 + 3

Mathematics

2 answers:

Tanya [424]2 years ago

8 0

$20 - 4 \times 4 \div 2 + 3$

Using BODMAS formula, we see that we have first divide, then multiply, then add and finally subtract
So
$20 - 4 \times 4 \div 2 + 3 \\ = 20 - 4 \times 2 + 3 \\ = 20 - 8 + 3 \\ = 23 - 8 \\ = 15$

<h3>Answer:</h3>

<h3>Hope it helps..</h3>

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fgiga [73]2 years ago

4 0

Answer:

Step-by-step explanation:

20-4×4÷2+2=14

you change the words into symbols

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Suppose that you were not given the sample mean and sample standard deviation and instead you were given a list of data for the

Troyanec [42]

Answer:

So, the sample mean is 31.3.

So, the sample standard deviation is 6.98.

Step-by-step explanation:

We have a list of data for the speeds (in miles per hour) of the 20 vehicles. So, N=20.

We calculate the sample mean :

$\mu=\frac{19 +19 +22 +24 +25 +27 +28+ 37 +35 +30+ 37+ 36+ 39+ 40+ 43+ 30+ 31+ 36+ 33+ 35}{20}\\\\\mu=\frac{626}{20}\\\\\mu=31.3$

So, the sample mean is 31.3.

We use the formula for a sample standard deviation:

$\sigma=\sqrt{\frac{1}{N-1}\sum_{i=1}^{N}(x_i-\mu)^2}$

Now, we calculate the sum

$\sum_{i=1}^{20}(x_i-31.3)^2=(19-31.3)^2+(19-31.3)^2+(22-31.3)^2+(24-31.3)^2+(25-31.3)^2+(27-31.3)^2+(28-31.3)^2+(37-31.3)^2+(35-31.3)^2+(30-31.3)^2+(37-31.3)^2+(36-31.3)^2+(39-31.3)^2+(40-31.3)^2+(43-31.3)^2+(30-31.3)^2+(31-31.3)^2+(36-31.3)^2+(33-31.3)^2+(35-31.3)^2\\\\\sum_{i=1}^{20}(x_i-31.3})^2=926.2\\$