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2 years ago

Solve the following proportion for u. 5/8=u/9 Round the answer to the nearest tenth.

Mathematics

1 answer:

Firlakuza [10]2 years ago

4 0

Answer:

5/10=u/9

explain answer: so to get this answer 5x8=40 so like the closes number to eight will be 9 and 10 but they said closes 10 so it will be 5/10 and =u/9 so answer= 5/10=u/9

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What inequality describes the weight range of a single nickel

Evgen [1.6K]

Answer:

4.806 g ≤ n ≤ 5.194 where n is the mass of a nickle.

Step-by-step explanation:

The problem tells us the weight can vary by .194 g, this means it can be up to .194 lighter and 194 heavier. Well what value is .194 lighter and .194 heavier? 4.806 and 5.194 respectively. So that means a nickle can be anywhere in that range, which tells us the inequality.

5 0

3 years ago

the highest recorded temperature was 134 degrees fahrenheit. The lowes is -128.6 degrees fahrenheit. What is the difference betw

Mazyrski [523]

Answer:

263.4 degree difference

Step-by-step explanation:

134+.4

134.4+128=262.4

8 0

2 years ago

Find the next term in the sequence 3, 6, 9, 15, 24,

leonid [27]

39, it is like the fibonacci sequence you take the 2 previous numbers and add them together to get the next number.

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2 years ago

What is the measure of angle Q to the nearest whole degree?<br> 43°<br> 49°<br> 53°<br> 58°

geniusboy [140]

Answer:

m∠Q ≈ 53°

Step-by-step explanation:

To find the measure of ∠Q, the law of cosines will need to be used. Lowercase letters represent the side lengths, while upper case letters represent angles.

In this situation, 'A' will be ∠Q. Therefore:

17² = 18² + 20² -2(18)(20)cosQ

Simplify:

289 = 324 + 400 -2(360)cosQ

Continue simplifying down:

-435 = -720cosQ

Divide both sides by '-720':

0.604 = cosQ

$cos^{-1}Q = 0.604$

m∠Q ≈ 52.83 or 53° rounded to the nearest whole degree.

3 0

2 years ago

Sin (x/2)= √2- sin (x/2) solve for the exact solutions in the interval (0, 2π)

serg [7]

$sin\left( \frac{x}{2} \right)=\sqrt{2}-sin\left( \frac{x}{2} \right)\implies sin\left( \frac{x}{2} \right)+sin\left( \frac{x}{2} \right)=\sqrt{2}\implies 2sin\left( \frac{x}{2} \right)=\sqrt{2} \\\\\\ sin\left( \cfrac{x}{2} \right)=\cfrac{\sqrt{2}}{2}\implies sin^{-1}\left[ sin\left( \cfrac{x}{2} \right) \right]=sin^{-1}\left( \cfrac{\sqrt{2}}{2} \right) \implies \cfrac{x}{2}= \begin{cases} \frac{\pi }{4}\\\\ \frac{3\pi }{4} \end{cases} \\\\[-0.35em] ~\dotfill$

$\cfrac{x}{2}=\cfrac{\pi }{4}\implies \boxed{x=\cfrac{\pi }{2}}~\hfill \cfrac{x}{2}=\cfrac{3\pi }{4}\implies \boxed{x=\cfrac{3\pi }{2}}$

5 0

2 years ago