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rodikova [14]
3 years ago
7

Destiny prefers investments that offer the highest possible returns, even if they are risky. Which of the following bonds is Des

tiny most likely to be interested in?
Chemistry
1 answer:
svp [43]3 years ago
8 0

Since Destiny is mostly interested in higher return, he will hence most likely invest in bonds with <em>very high risk rate</em>. Hence, Destiny will most likely be interested in Junk bond.

  • Both Municipal and savings bond are usually backed up by the government as as such they are safer to invest in. However, they have low rate of return.

  • Corporate bonds are usually issued by profit - oriented companies and organizations and have a <em>higher rate of return than municipal</em> and savings bond.

  • Junk bonds are a form of corporate bond with very high level of risk which is compensated by a very high return rate compared to other corporate bonds. There is a <em>higher tendency that companies that issue junk bonds will default on their debt</em>.

Therefore, Destiny will most likely be interested in a Junk bond.

Learn more:brainly.com/question/17405470?referrer=searchResults

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The equilibrium-constant expression for a reaction written in one direction is the __________ of the one for the reaction writte
VLD [36.1K]

Answer:

  • <u>    reciprocal   </u>

Explanation:

The <em>equilibrium constant</em> for an <em>equilibrium reaction </em>is the ratio of the equilibrium constant for the forward reaction, Kf, to the equilibrium constant for the reverse reaction, Kr:

  • For A ⇄ B

  • The forward reaction is: A → B, with rate constant is Kf = K₁ and
  • The reverse reaction is: B → A, with rate constant Kr = K₂

            K_{eq}=\dfrac{K_f}{K_r}=\dfrac{K_1}{K_2}

When you write the reaction in the other reaction, the forward and the reverse reaction are exchanged:

  • For B ⇄ A

  • The forward reaction is B → A, with rate constant Kf = K₂
  • The reverse reaction is A → B, with rate constant Kr = K₁

             

             K'_{eq}=\dfrac{K_f}{K_r}=\dfrac{K_2}{K_1}

As you see:

          K'_{eq}=\dfrac{1}{K_{eq}}

Thus, <em>the equilibrium-constant expression for a reaction written in one direction is the </em><em><u>    reciprocal</u></em><em>___</em><em> of the one for the reaction written for the reverse direction.</em>

8 0
4 years ago
A 32.8 g iron rod, initially at 22.4 C, is submerged into an unknown mass of water at 63.1 C, in an insulated container. The fin
laila [671]

Answer:

mass water = 32.4 g

Explanation:

specific heat iron = 0.450 J/g°C

specific heat water = 4.18 J/g°C

32.8 x 0.450 ( 59.1 - 22.4) + mass water x 4.18 ( 59.1- 63.1)=0

541.7 - mass water x 16.7 = 0

mass water = 32.4 g

3 0
3 years ago
Can we move only one electron from its orbit to another orbit of lower energy without moving other electrons of the atom? well i
Mrac [35]
Yes, it can happen.

If all the lower energy orbits are already filled with electrons, then it cannot happen since the lower orbitals will already be full, hence another electron will have to move.

However, if the lower energy orbits are not full (for instance if one excited electron goes back to its normal state), then it can happen.
4 0
3 years ago
5. A grouping of organisms based on shared characteristics is called
lidiya [134]
Classification ,
correct me if i’m wrong
8 0
3 years ago
Read 2 more answers
When hydrochloric acid is poured over potassium sulfide, 42.5 mL of hydrogen sulfide gas is produced at a pressure of 756 torr a
EastWind [94]
<h2>Answer:</h2>0.1899grams

<h2>Explanations:</h2>

The balanced chemical reaction between hydrochloric acid and potassium sulfide is as shown:

K_2S+2HCl\to H_2S+2KCl

Based on stoichiometry, we can see that 1 mole of potassium sulfide reacted to form 1 mole of hydrogen sulfide.

Get the mole of hydrogen sulfide gas (H2S) using the ideal gas equation expressed as:

\begin{gathered} PV=\text{nRT} \\ n=\frac{PV}{RT} \end{gathered}

P is the pressure of the gas (in atm) = 0.994737atm (756torr)

V is the volume of the gas = 42.5mL = 0.0425L

T is the temperature (in Kelvin) = 26 + 273 = 299K

R is the gas constant = 0.0821 L*atm/mole * K

Substitute these values into the formula as shown:

\begin{gathered} n=\frac{0.994737\cancel{\text{atm}}\times0.0425\cancel{L}}{0.0821\frac{\cancel{L}\cdot\cancel{\text{atm}}}{\text{mole}\cdot\cancel{K}}\times299\cancel{K}} \\ n=\frac{0.994737\times0.0425}{0.0821\times299} \\ n=\frac{0.0422763225}{24.5479} \\ n=0.00172\text{moles} \end{gathered}

Since the number of moles of hydrogen sulfide is 0.00172moles, the number of moles of potassium sulfide will also be 0.00172 moles (based on stoichiometry)

Get the mass of potassium sulfide that reacted using the formula:

\text{Mass}=number\text{ of moles}\times molar\text{ mass}

Number of moles of K2S = 0.00172 moles

Molar mass of K2S = 110.262 g/mol

Substitute into the formula for calculating the mass;

\begin{gathered} \text{Mass}=0.00172\cancel{\text{moles}}\times\frac{110.262g}{\cancel{\text{mole}}} \\ \text{Mass}=0.1899\text{grams} \end{gathered}

Therefore the mass of potassium sulfide that reacted (in grams) is approximately 0.1899grams

3 0
1 year ago
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