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cupoosta [38]
3 years ago
5

Which statement is true of the particles that make up a substance?

Chemistry
1 answer:
victus00 [196]3 years ago
8 0

Particles in a gas have more energy than particles in a liquid. Because in gaseous state particles are free to move around due to which kinetic energy of molecule or gas increases and hence overall energy increases

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What is the quantum number set of the ground-state electron that is found in lithium (Li) but not in helium (He)?
statuscvo [17]
The electron configuration of lithium atom is: Li:[He]2s^1

The number "2" is the value of the principal quantum number "n". Letter "s" is associated with the value of secondary quantum number "l" and it is equal to zero. The value of "m" (or magnetic quantum number) is zero too. The quantum number set for the highest energy electron will be (2, 0, 0, 1/2).
3 0
3 years ago
Consider a solution that contains 0.274 M potassium chloride and 0.155 M magnesium chloride.
solong [7]

Answer:

Concentration of chloride ions = 0.584M

Explanation:

The step by step calculations is shown as attached below.

3 0
3 years ago
Which of the following is a product of aerobic respiration?
sasho [114]

Answer:

The product of aerobic respiration is Carbon dioxide.

Explanation:

  • The process of breaking down glucose to produce energy and waste products is called respiration. Livings beings need respiration process to generate energy so  that they can survive.
  • The types of respiration are : Anaerobic and aerobic respiration.
  • Aerobic respiration takes place in presence of oxygen and produces large amount of energy.
  • The final product of aerobic respiration are carbon dioxide, water and 38 ATP of energy.
3 0
4 years ago
Read 2 more answers
What is the density of an object that has a mass of 6.5 g and when placed in water displaces the volume from 4.5mL to 11.8mL? ro
KengaRu [80]

Answer:

\rho =0.9g/mL

Explanation:

Hello,

In this case, due to the volume displacement caused the by the object's submersion, it's volume is:

V=11.8mL-4.5mL=7.3 mL

In such a way, considering the mathematical definition of density, it turns out:

\rho =\frac{m}{V}=\frac{6.5g}{7.3mL}\\  \\\rho =0.89g/mL

Rounding to the nearest tenth we finally obtain:

\rho =0.9g/mL

Regards.

3 0
3 years ago
When calcium carbonate is added to hydrochloric acid, calcium chloride, carbon dioxide, and water are produced.
sp2606 [1]

Answer:

Mass of CaCl₂ =  20 g

CaCO is presewnt in excess.

Mass of of CaCO₃ remain unreacted =  7.007 g

Explanation:

Given data:

Mass of calcium carbonate = 25 g

Mass of hydrochloric acid = 13.0 g

Mass of calcium chloride produced = ?

Chemical equation:

CaCO₃ + 2HCl  →  CaCl₂  + H₂O + CO₂

Number of moles of CaCO₃:

Number of moles of CaCO₃ = Mass /molar mass

Number of moles of CaCO₃= 25.0 g / 100.1 g/mol

Number of moles of CaCO₃ = 0.25 mol

Number of moles of HCl:

Number of moles of  HCl = Mass /molar mass

Number of moles of HCl = 13.0 g / 36.5 g/mol

Number of moles of HCl = 0.36 mol

Now we will compare the moles of CaCl₂ with HCl and CaCO₃ .

                  CaCO₃         :               CaCl₂

                    1                 :               1

                 0.25              :            0.25

                HCl                :                CaCl₂

                 2                   :                    1

                 0.36            :                  1/2 × 0.36 = 0.18 mol

The number of moles of CaCl₂ produced by HCl are less it will be limiting reactant.

Mass of CaCl₂ = moles × molar mass

Mass of CaCl₂ =0.18 mol × 110.98 g/mol

Mass of CaCl₂ =  20 g

The calcium carbonate is present in excess.

                HCl                :                CaCO₃

                 2                   :                    1

                 0.36            :                  1/2 × 0.36 = 0.18 mol

So, 0.18 moles react with 0.36 moles of HCl.

The moles of CaCO₃ remain unreacted = 0.25 -0.18

The moles of CaCO₃ remain unreacted = 0.07 mol

Mass of of CaCO₃ remain unreacted = Moles × molar mass

Mass of of CaCO₃ remain unreacted = 0.07 mol × 100.1 g/mol

Mass of of CaCO₃ remain unreacted =  7.007 g

7 0
3 years ago
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