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2 years ago

PLS HELP, 20 POINTS (easy question but I'm dummy)

Mathematics

1 answer:

yarga [219]2 years ago

8 0

Answer:

diagonals are perpendicular......its not true

Step-by-step explanation:

hiiii

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Solve the formula for the indicated variable.<br> T(r+s)=rs, for r<br> (Simplify your answer.)

yaroslaw [1]

Answer:

$R = \frac{-TS}{(T-S)}$

Step-by-step explanation:

First, distribute all terms

$T(R+S) =RS\\TR + TS =RS$

Get all terms with R onto the same side

$TR + TS = RS\\TR - RS = -TS$

Factor out the R

$R(T-S)=-TS$

Divide by (T-S) to isolate R

$R = \frac{-TS}{(T-S)}$

5 0

3 years ago

Read 2 more answers

The grades for the latest statistics exam are normally distributed. The mean was 93 with a standard deviation of 4. What is the

olga_2 [115]

Answer:68.27%

Step-by-step explanation:

TI84

2nd distr

normalcdf(89,97,93,4)

3 0

3 years ago

The proportion of left handed people in the population is about 0.10. Suppose a random sample of 300 people is observed. (a) Wha

pantera1 [17]

Answer: $(\hat{p})\sim N(0.10,\ 0.017)$

Step-by-step explanation:

Sampling distribution of the sample proportion $(\hat{p})$ :

$(\hat{p})\sim N(p,\ \sqrt{\dfrac{p(1-p)}{n}})$

The sampling distribution of the sample proportion $(\hat{p})$ has mean = $\mu_{\hat{p}}=p$ and standard deviation = $\sigma_{\hat{p}}=\sqrt{\dfrac{p(1-p)}{n}}$ .

Given : The proportion of left handed people in the population is about 0.10.

i.e. p=0.10

sample size : n= 300

Then , the sampling distribution of the sample proportion $(\hat{p})$ will be :-

$(\hat{p})\sim N(0.10,\ \sqrt{\dfrac{0.10(1-0.10)}{300}})$

$(\hat{p})\sim N(0.10,\ \sqrt{0.0003})$

$(\hat{p})\sim N(0.10,\ 0.017)$ (approx)

Hence, the sampling distribution of the sample proportion $(\hat{p})$ is $(\hat{p})\sim N(0.10,\ 0.017)$

8 0

2 years ago

Can someone please help me with this math question

lora16 [44]

Answer:

C'(4,4)

Step-by-step explanation:

The dilation of quadrilateral ABCD over the origin by a scale factor of 2 has the rule

(x,y)→(2x,2y)

So,

A(-3,-1)→A'(-6,-2)
B(-1,1)→B'(-2,2)
C(2,2)→C'(4,4)
D(3,-2)→D'(6,-4)

Hence, the coordinates of the image point C' are (4,4) (see attached diagram for details)

8 0

3 years ago

Read 2 more answers

Solve for x<br> 5x + 2 = 52

Stolb23 [73]

5x+2=52

5X=52-2

5x=50

5x/5=50/5

X=10

4 0

2 years ago