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NemiM [27]
3 years ago
14

Qbasic program to check whether the given number is odd or even​

Computers and Technology
2 answers:
Iteru [2.4K]3 years ago
6 0

Answer:

CLS

INPUT "Enter a Number: ", n

IF n MOD 2 = 0 THEN

PRINT "Input Number is Even"

END IF

IF n MOD 2 = 1 THEN

PRINT "Input Number is Odd"

END IF

END

andrey2020 [161]3 years ago
6 0

Explanation:

CLS

INPUT "Enter a number:",N

IF N MOD 2=0 THEN

PRINT "given number is even"

ELSE

PRINT"given number is odd"

END IF

END

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Create a list with 5 numbers and find the smallest and largest number in the list and also the sum and product of the numbers in
rusak2 [61]

Answer:

Explanation:

The following code is written in Java. It creates 5 random integers and saves them to a list called myList. Then it loops through that list and checks each one until the largest and smallest values are obtained. Finally, it uses these values to calculate the sums and products as requested. The program has been tested and the output can be seen in the attached image below.

import java.util.ArrayList;

import java.util.Arrays;

import java.util.Random;

import java.util.Scanner;

class Brainly {

   public static void main(String[] args) {

       Random rand = new Random();

       ArrayList<Integer> myList = new ArrayList<>();

       for (int i = 0; i< 5; i++) {

           int mynum = rand.nextInt(20);

           myList.add(mynum);

       }

       int largest = myList.get(0);

       int smallest = myList.get(0);

       int sum = 0;

       int product = 1;

       int sumLargestandSmallest, productLargestandSmallest;

       for (int x : myList) {

           if (x > largest) {

               largest = x;

           }

           if (x < smallest) {

               smallest = x;

           }

           sum += x;

           product *= x;

       }

       sumLargestandSmallest = largest + smallest;

       productLargestandSmallest = largest * smallest;

       System.out.println("List" + Arrays.toString(myList.toArray()));

       System.out.println("Smallest: " + smallest);

       System.out.println("Largest: " + largest);

       System.out.println("Sum: " + sum);

       System.out.println("Product: " + product);

       System.out.println("Sum of Smallest and Largest: " + sumLargestandSmallest);

       System.out.println("Product of Smallest and Largest: " + productLargestandSmallest);

   }

}

6 0
3 years ago
Which type of software coordinates the hardware and software of a computer to work efficiently and productively?
Mariana [72]
A. the operating system handles the I/O devices with the cpu, :)
7 0
4 years ago
Read 2 more answers
Paul listed the websites he searched to find information on a career in biology ​
balandron [24]

Answer:

The frustration-aggression hypothesis

Explanation:

7 0
3 years ago
Define a method pyramidVolume with double parameters baseLength, baseWidth, and pyramidHeight, that returns as a double the volu
marysya [2.9K]
<h2>Question:</h2>

Define a method pyramidVolume with double parameters baseLength, baseWidth, and pyramidHeight, that returns as a double the volume of a pyramid with a rectangular base. Relevant geometry equations:

Volume = base area x height x 1/3

Base area = base length x base width.

(Watch out for integer division)

import java.util.Scanner;

public class CalcPyramidVolume {

   /* Your solution goes here */

   public static void main (String [] args) {

     System.out.println("Volume for 1.0, 1.0, 1.0 is: " + pyramidVolume(1.0, 1.0,   1.0));

     return;

    }

}

<h2>Answer:</h2><h2></h2>

import java.util.Scanner;

public class CalcPyramidVolume {

   /* Your solution goes here */

   public static void main (String [] args) {

       System.out.println("Volume for 1.0, 1.0, 1.0 is: " + pyramidVolume(1.0, 1.0, 1.0));

       return;

   }

   

   //Begin method definition

   public static double pyramidVolume(double baseLength, double baseWidth, double pyramidHeight){

       

       //First, calculate the base area of the pyramid

       //store the result in a double variable

       double baseArea = baseLength * baseWidth;

       

       //Then, calculate the volume of the pyramid

       //using the base area and the base width

       double volume = 1 / 3.0 * baseArea * pyramidHeight;

       

       //return the volume

      return volume;

   }

}

<h2>Output:</h2>

Volume for 1.0, 1.0, 1.0 is: 0.3333333333333333

<h2>Explanation:</h2>

The code above contains comments explaining the important lines of the code. The output of the code has also been provided above.

The parts of the code that are worth noting are:

(i) The return type of the method pyramidVolume should be a <em>double</em> since calculations are done using <em>double</em> values. i.e the method header should be written as

<em>public static double pyramidVolume(){</em>

<em>}</em>

<em />

(ii) The method requires three(3) parameters of type double: baseLength, baseWidth and pyramidHeight. These should be included in the method. Therefore, the complete header definition should be:

<em>public static double pyramidVolume(double baseLength, double baseWidth, double pyramidHeight){</em>

<em />

<em>}</em>

(iii) The formula for calculating the volume of the pyramid should be:

volume = 1 / 3.0 * baseArea * baseWidth;

Rather than;

volume = 1 / 3 * baseArea * baseWidth;

This is because integer division yields integer result. If 1 / 3 is evaluated, the result will be 0 since the decimal part will be truncated thereby making the result of the volume = 1 / 3 * baseArea * baseWidth will be 0.

Therefore, the work around for that should be to write 1 / 3.0 or 1.0 / 3.0 or 1.0 / 3.

(iv) After the calculation, the result of volume should be returned by the method. This will enable a proper call by the main method for execution.

7 0
3 years ago
write two paragraphs (at least 5 sentences each) about what President Biden and Vice-President Harris plan to do during the firs
frozen [14]

Answer:

writing one in comments bec i don't have time for both sorry

4 0
3 years ago
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