Answer:
3:20 3/20 3.20
Step-by-step explanation:
Answer:
6(x-8)=5-2x
Step-by-step explanation:
let the number be x
so we have six times the difference between a number and 8
that is 6(x-8).
is equal to 5 less than twice the number ..we have
=5-2x.
therefore, our answer becomes:
6(x-8)=5-2x
Answer:
B
Step-by-step explanation:
Please mark as brainliest
Answer:
Try going on D.e.s.m.o.s.c.o.m it worked for me when I had something like this
Step-by-step explanation:
GURL POWER
Answer: The number is 26.
Step-by-step explanation:
We know that:
The nth term of a sequence is 3n²-1
The nth term of a different sequence is 30–n²
We want to find a number that belongs to both sequences (it is not necessarily for the same value of n) then we can use n in one term (first one), and m in the other (second one), such that n and m must be integer numbers.
we get:
3n²- 1 = 30–m²
Notice that as n increases, the terms of the first sequence also increase.
And as n increases, the terms of the second sequence decrease.
One way to solve this, is to give different values to m (m = 1, m = 2, etc) and see if we can find an integer value for n.
if m = 1, then:
3n²- 1 = 30–1²
3n²- 1 = 29
3n² = 30
n² = 30/3 = 10
n² = 10
There is no integer n such that n² = 10
now let's try with m = 2, then:
3n²- 1 = 30–2² = 30 - 4
3n²- 1 = 26
3n² = 26 + 1 = 27
n² = 27/3 = 9
n² = 9
n = √9 = 3
So here we have m = 2, and n = 3, both integers as we wanted, so we just found the term that belongs to both sequences.
the number is:
3*(3)² - 1 = 26
30 - 2² = 26
The number that belongs to both sequences is 26.
